Answer:
6.19 x 
m/
Explanation:
For this exercise we need to sum the forces on the y-axis and x-axis as follows:
∑
= N - mg = m.
= 0
From the exercise, we deduce there is no motion in y-axis, so:
N = mg
Then for x-axis we have:
∑
= H - 
= m.
= 0
Now, from the exercise we deduce that we are looking for the greatest static friction which means to have the maximun static friction to start moving, so at this point the acceleration is zero, so we can find horizontal force (H), which then will act in the airplane to move it. Therefore we have:
H = = 
= 
N = mg
H = (0.76)(84Kg)(9.8m/)
H = 625.63 N
Now we apply this force to the weight of the plane to find the greatest acceleration the mann can give to start moving the plane.
a = 
= 
a = 
a = 6.19 x m/
R = ρl/A
Where R = Resistance in Ohms, Ω, ρ = Resistivity in Ωm, l = Length in m.
Area in m²
ρ = Resistivity = 3.14 * 10⁻⁸ Ωm, Length l = 12m,
Area = πr² = π* (2*10⁻⁴)² m² ≈ 3.14 * (2*10⁻⁴)² m²
R = ρl/A
≈ 3.14 * 10⁻⁸ * 12 / (3.14 * (2*10⁻⁴)²)
≈ 3
Resistance, R ≈ 3 Ω
The answer is 6 and a half days
Answer: 0.235
Explanation:
Given data.
M1 = 0.91 Kg
M2 = 2kg
L = 0.95m
N = 35rpm
t = 10.44secs
Solution:
• we first solve for the center of gravity
•we calculate our moment of inertia
• we calculate the angular velocity
• we solve for our torque ( t )
Answer:
Magnetic field is in south west direction .
Explanation:
Let us represent various direction by i , j, k . i representing east , j representing north and k representing vertically upward direction .
magnetic field is represented vectorially as follows
B = B₀ ( - i - j )
In the first case velocity of electron
v = v k
Force = q ( v x B )
= -e [ vk x B₀ ( - i - j ) ]
= evB₀ ( j -i )
Direction of force is north -west .
In the second case velocity of electron
v = vj
Force = -e [ vj x B₀ ( - i - j ) ]
= - evB₀ k
force is downward
In the third case, velocity of electron
v = v( -j +i )
Force = -e [ v( -j +i ) x B₀ ( - i - j ) ]
= 2 evB₀ k
Force is upward.
