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2 years ago

How would you characterize William's relationship with his father? In what ways did his father help shape William's outlook?

Physics

1 answer:

Aleksandr [31]2 years ago

3 0

William's father shaped William's outlook on life when he was younger due to his bravery.

<h3>What was the relationship between William and his father?</h3>

The impact of significant others in the life of a person can not be over emphasized. These significant others often serve as role models and help to develop the individuality and personality of people.

The life of William was shaped quite well by his father because the both of them had a cordial relationship with each other. William's father shaped William's outlook on life when he was younger due to his bravery.

Learn more about William and his father:brainly.com/question/4066623

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If you do 1500 J of work hoisting a 20 kg bale of hay , to what height did you lift it

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Explanation:

W = PE

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1500 J = (20 kg) (9.8 m/s²) h

h = 7.65 m

Round as needed.

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3 years ago

What is the impulse of a 3kg object accelerating from rest to 12m/s?

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3 years ago

calculate earths velocity of approach toward the sun when earth in its orbit is at an extremum of the latus rectum through the s

IceJOKER [234]

Answer:

Hello your question is incomplete below is the complete question

Calculate Earths velocity of approach toward the sun when earth in its orbit is at an extremum of the latus rectum through the sun, Take the eccentricity of Earth's orbit to be 1/60 and its Semimajor axis to be 93,000,000

answer : V = 1.624* 10^-5 m/s

Explanation:

First we have to calculate the value of a

a = 93 * 10^6 mile/m * 1609.344 m

= 149.668 * 10^8 m

next we will express the distance between the earth and the sun

$r = \frac{a(1-E^2)}{1+Ecos\beta }$ --------- (1)

a = 149.668 * 10^8

E (eccentricity ) = ( 1/60 )^2

$\beta$ = 90°

input the given values into equation 1 above

r = 149.626 * 10^9 m

next calculate the Earths velocity of approach towards the sun using this equation

$v^2 = \frac{4\pi^2 }{r_{c} }$ ------ (2)

Note :

Rc = 149.626 * 10^9 m

equation 2 becomes

( $V^2 = (\frac{4\pi^{2} }{149.626*10^9})$

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3 years ago

A ball is dropped from rest from a height h above the ground. another ball is thrown vertically upwards from the ground at the i

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while the position of the second ball, thrown with initial velocity $v$ , is

$y_2=vt-\dfrac g2t^2$

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$\dfrac h2=h-\dfrac g2t^2$

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$\implies t=\sqrt{\dfrac hg}$

We want the second ball to reach the same height at the same time, so that

$\dfrac h2=v\sqrt{\dfrac hg}-\dfrac g2\left(\sqrt{\dfrac hg}\right)^2$

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3 years ago

What happens when the voltage increases and the resistance stays the same in a electrical circuit?

Orlov [11]

Answer:

The current in the circuit increases

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