This Process is called fertilization
Answer:
2H⁺(aq) + 2OH⁻(aq) --> 2H2O(l)
Explanation:
2HBr(aq)+Ba(OH)2(aq)⟶2H2O(l)+BaBr2(aq)
We break the compounds into ions. Only compounds in the aqueous form can be turned into ions.
The ionic equation is given as;
2H⁺(aq) + 2Br⁻(aq) + Ba²⁺(aq) + 2OH⁻(aq) --> 2H2O(l) + Ba²⁺(aq) + 2Br⁻(aq)
Upon eliminating the spectator ions; The net equation is given as;
2H⁺(aq) + 2OH⁻(aq) --> 2H2O(l)
Answer:
C) sp2 and sp2
Explanation:
The hybridization depens on the ammount and type of bonds the atom analized has in the molecule.
For example:
- A C atom bonded to 4 H atoms has a sp3 hybridization.
- A C atom bonded to 2 H atoms and to 1 C with a double bond (like in ethene) has a sp2 hybridization
- A C bonded to 1 H and 1 C with a triple bond (like in ethyne) has a sp hybridization.
Analyzing the type and amount of unions of the nitrogen and the carbonyl you will be able to determine the hybridization.
In the imine, the N atom has a double bond to a C and a simple bond two other C, plus the lone pair of electrons (counts as a bond) so it will have a sp2 hybridization.
In the carbonyl, the C has two simple bonds to other C and a double bond to an oxygen atom. It will also have a sp2 hybridization
Answer:
0.0140 M H₂C₆H₆O₆.
Explanation:
- We should mention the relation: <em>Ka = α²C,</em>
Where, Ka is the dissociation constant of the acid.
α is the degree of ionization of the acid.
C is the concentration if the acid.
<em>The percent of ionization (α %) = α x 100.</em>
α = √Ka/C
∴ α is inversely proportional to the concentration of the acid.
<em>So, the acid with the lowest concentration has the greatest percent ionization.</em>
