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stira [4]
3 years ago
12

A student measures out 5 mL of calcium chloride solution into a small container and 5 mL of sodium carbonate solution in another

small container. The total mass of both chemicals and the containers they are in is 15.5 g. When the student combined the two clear liquids, a gooey, cloudy precipitate formed. What would the total mass of the products and the two containers be after this reaction took place?
Chemistry
2 answers:
sergij07 [2.7K]3 years ago
6 0

Answer:

15.5

Explanation:

in a chemical reaction, mass is conserved

so mass after reaction = mass before reaction = 15.5 g

qwelly [4]3 years ago
3 0

Answer:

15.5g

Explanation:

"The total mass of both chemicals and the containers they are in is 15.5 g." After a chemical reaction, by conservation of mass, the total mass of the products and the two containers after reaction is the same at 15.5g.

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7 0
2 years ago
The value of K at constant temperature depends on the amounts of reactants and products that are mixed together initially. A lar
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Answer:

a) K = [ CO2(g) ]

⇒ the [ CaCO3(s) ] does not appear in the denominator of the equilibrium constant, as it is a pure solid substance.

b) Kp = K (RT)∧Δn

⇒ the values of K and Kp are not the same

c) K >> 1, The reaction has a high yield and is said to be shifted to the right. then the rate of the forward reaction is greater than the rate of the reverse reaction at equilibrium.

Explanation:

a) CaCO3(s) ↔ CaO(s) + CO2(g)

⇒ K = [ CO2(g) ]

∴ the [ CaCO3(s) ] does not appear in the denominator of the equilibrium constant, as it is a pure solid substance.

b) H2(g) + F2(g) ↔ 2 HF(g)

⇒ K = [ HF(g) ] ² / [ F2(g) ] * [ H2(g) ]

⇒ Kp = PHF² / PF2 * PH2

for ideal gas:

PV = RTn

⇒ P = n/V RT = [ ] RT

⇒ Kp = K (RT)∧Δn

⇒ the values of K and Kp are not the same.

c) K >> 1, The reaction has a high yield and is said to be shifted to the right. then the rate of the forward reaction is greater than the rate of the reverse reaction at equilibrium.

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