Answer with Explanation:
Electric field:It is the force per unit charge experienced by rest charge at any given point.
It is the area around the charge which is placed at rest.It is represented by E.
Mathematical formula:
Magnetic field:It is an area around moving charge in which moving charge particle experienced magnetic force in that area.
Magnetic field is represented by B.
Mathematical formula :
Where B=Magnetic field
q=Charge on particle
v=Velocity of particle
F=Magnetic force exert on particle
Path for transmitting electric current. An electric circuit includes a device that gives energy to the charged particles constituting the current, such as battery or a generator; devices that use current, such as lamps, electric motors, or computers; and the connecting wires or transmission lines
Note : Be careful with speed and velocity, even the formula is same that
1. If we would like to find the velocity, we must calculate the distance from initial to final,
,
2. If we would like to find the speed, we must calculate the total distance that travelled (
.
So, in this question, because it return back to its initial point so (delta)x = 0, so average velocity is 0 m/s.
Answer:
The distance that separates the two particles is 7.42 cm.
Explanation:
Given;
the mass of each particle, m = 3 mg = 3 x 10⁻⁶ kg
the magnitude of charge of each particle, q = 6.0 nC
speed of each particle, v = 5.0 m/s
a = v/t
where;
a is the acceleration of the two particles
v is the final velocity
t is time
v = u + gt
5 = 0 + 9.8t
5 = 9.8t
t = 5/9.8
t = 0.51 s
a = v/t
a = 5/0.51 = 9.8 m/s²
Total force on the two particles = (2m)a = (2* 3 x 10⁻⁶)9.8
F = 5.88 x 10⁻⁵ N
Substitute in the value of F in the above equation and calculate r
where;
k is coulomb's constant = 8.99 x 10⁹ Nm²/c²
r is the distance of separation between the two particles
Therefore, the distance that separates the two particles at the instant when each has a speed of 5.0 m/s, is 7.42 cm.
Answer:
Potential energy will be 
Explanation:
We have given the height of the basin is h = 6 m
Area of the basin 
Volume 
Density 
We know that mass is given by 
We know that potential energy is given by 
