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ra1l [238]
3 years ago
14

A roller coaster is moving at 25m/s at the bottom of a hill. Three seconds later it reaches the top of the hill moving at 10m/s.

What was the acceleration of the coaster
Physics
1 answer:
marishachu [46]3 years ago
8 0

Answer:

5 m/s^{2}

Explanation:

acceleration is defined as the rate of change of velocity per unit time. Therefore, acceleration, a=\frac {\triangle v}{\triangle t}

where \triangle v is change in velocity and t is time

Substituting initial and final velocities with 25 m/s and 10 m/s then using time as given in the question of 3 s then

a=\frac {25-10}{3}=\frac {15}{3}=5 m/s^{2}

Therefore, the acceleration is 5 m/s^{2}

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Explanation:

Step one:

given

distance = 20meters

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let us solve for the final velocity

velocity = distance/time

velocity= 20/2

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v^2=u^2+2as\\\\10^2=0^2+2*a*20\\\\100=40a

divide both sides by 40

a= 100/40\\\\a=10/4\\\\a= 5/2\\\\a= 2.5m/s^2

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