A roller coaster is moving at 25m/s at the bottom of a hill. Three seconds later it reaches the top of the hill moving at 10m/s.
1 answer:
Answer:
Explanation:
acceleration is defined as the rate of change of velocity per unit time. Therefore, acceleration,
where is change in velocity and t is time
Substituting initial and final velocities with 25 m/s and 10 m/s then using time as given in the question of 3 s then
Therefore, the acceleration is
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a) 0.26 h
b) 71.4 km
Explanation:
a)
In order to solve the problem, we have to know what is the final velocity of the car.
Here, we assume that the final velocity reached by the car is
Therefore, we can find the time taken by the car to reach this velocity by using the suvat equation:
where:
u = 250 km/h is the initial velocity
is the acceleration of the car
v = 300 km/h is the final velocity
t is the time
Solving for t, we find:
b)
In order to find the distance covered by the car, we can use the following suvat equation:
where:
s is the distance covered
u is the initial velocity
a is the acceleration
t is the time
For the car in this problem, we have:
u = 250 km/h
t = 0.26 h (calculated in part a)
Therefore, the distance covered is
Answer:
And after do all the operations we got:
And that would be the final answer for this case.
Explanation:
For this case we can use the fomrula for the fraction of incident particles scattered by an angle , given by:
Where:
represent the charge of the projectile (Z1=2)
is the target charge (z2=79)
represent the kinetic energy of incident particle
n represent the density of target particles (we need to find it first)
represent the thicknss of the foil
The first step would be calculate the density of target particles with the following formula:
Where:
the Avogadro's number
represent the atoms per molecule
represent the molecular weigth
If we replace we got:
Now we can calculate the fraction of 5 MeV alpha particles that would be scatteres with angle higher than 8 degrees in a piece of thickness
And using the first formula we got:
And after do all the operations we got:
And that would be the final answer for this case.