The cart experiences a frictional force which is directly proportional to its weight. This means that there must be a force applied on the car to balance the forces on the car to produce a net force of 0.
This is in accordance to Newton's first law which states that an object at rest will remain at rest and an object in motion will remain in motion unless an external force acts on it. The force must be a resultant force.
Therefore, the force needed increases with the total weight of the cart as well as with the added mass in a linear manner.
Answer:
The current on the water layer = 1.64×10^-3A
Explanation:
Let's assume that the radius given for the string originates from the centre of the string. The equation for determining the current in the water layer is given by:
I = V × pi[(Rwater + Rstring)^2 - (Rstring)^2/ ( Resitivity × L)
I =[ 166×10^6 ×3.142[(0.519×10^-4) + (2.15×10^-3])^2 - ( 2.15×10^-3)^2] / ( 183 × 831)
I =[ 521572000(4.848×10^6)- 4.623×10^-6]/ 154566
I = 252.83 -(4.623×10^-6)/ 154566
I = 252.83/154566
I = 1.64× 10^-3A
<h3><u>Full Question:</u></h3>
A 2-kg toy car accelerates from 5 to 10 m/s in 2 seconds. Find the applied force.
<h2><u>Answer:</u></h2>
Force applied is
.
<h3><u>Explanation:</u></h3>
Force is defined as something which changes or tends to change the velocity of a body. And acceleration is defined as the rate of change of velocity of a body per time. Both of them are vector quantities.
The initial velocity of the body = 5 m/s.
The final velocity of the body = 10 m/s.
So the change in velocity = 10 - 5 m/s = 5m/s.
Time period = 2 seconds.
So acceleration =
= 
The force is defined as the product of mass and acceleration of the body.
Mass of body = 2 kg.
So, force applied =
. =
.