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ra1l [238]
3 years ago
14

A roller coaster is moving at 25m/s at the bottom of a hill. Three seconds later it reaches the top of the hill moving at 10m/s.

What was the acceleration of the coaster
Physics
1 answer:
marishachu [46]3 years ago
8 0

Answer:

5 m/s^{2}

Explanation:

acceleration is defined as the rate of change of velocity per unit time. Therefore, acceleration, a=\frac {\triangle v}{\triangle t}

where \triangle v is change in velocity and t is time

Substituting initial and final velocities with 25 m/s and 10 m/s then using time as given in the question of 3 s then

a=\frac {25-10}{3}=\frac {15}{3}=5 m/s^{2}

Therefore, the acceleration is 5 m/s^{2}

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The current on the water layer = 1.64×10^-3A

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3 0
3 years ago
A 2-kg toy car accelerates from 5 to 10 m/s.
andre [41]
<h3><u>Full Question:</u></h3>

A 2-kg toy car accelerates from 5 to 10 m/s in 2 seconds. Find the applied force.

<h2><u>Answer:</u></h2>

Force applied is 5\frac {kgm} {s^2}.

<h3><u>Explanation:</u></h3>

Force is defined as something which changes or tends to change the velocity of a body. And acceleration is defined as the rate of change of velocity of a body per time. Both of them are vector quantities.

The initial velocity of the body = 5 m/s.

The final velocity of the body = 10 m/s.

So the change in velocity = 10 - 5 m/s = 5m/s.

Time period = 2 seconds.

So acceleration =\frac52 m/s^2= 2.5 m/s^2

The force is defined as the product of mass and acceleration of the body.

Mass of body = 2 kg.

So, force applied =  2 \times 2.5 kgm/s^2. =5kgm/s^2.

4 0
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