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cricket20 [7]
3 years ago
11

Ken wants to jump and have some fun too! Barbie loans Ken her bungee cord. Is this a good idea? Explain with evidence and reason

ing. (barbie bungee jump lab)
Physics
2 answers:
NeX [460]3 years ago
6 0

Answer:

To ensure a safe and thrilling jump you will determine the relationship between the jump height and the  number of rubber bands used to make the bungee cord. You must allow your Barbie doll to come as  close to the floor as possible without sustaining any injuries or fatalities.

Explanation:

aliina [53]3 years ago
5 0

Answer:To ensure a safe and thrilling jump you will determine the relationship between the jump height and the

number of rubber bands used to make the bungee cord. You must allow your Barbie doll to come as

close to the floor as possible without sustaining any injuries or fatalities.

Explanation:

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A farmer lifts his hay bales into the top loft of his barn by walking his horse forward with a constant velocity of 1 ft/s. Dete
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Answer:

The velocity of the hay bale is - 0.5 ft/s and the acceleration is 6.25\times 10^{- 3} ft/s^{2}

Solution:

As per the question:

Constant velocity of the horse in the horizontal, v_{x} = 1 ft/s

Distance of the horse on the horizontal axis, x = 10 ft

Vertical distance, y = 20 ft

Now,

Apply Pythagoras theorem to find the length:

20^{2} + 10^{2} = l^{2}

l^{2}= 500

Now,

x^{2} + y^{2} = 500                            (1)

Differentiating equation (1) w.r.t 't':

2x\frac{dx}{dt} + 2y\frac{dy}{dt} = 0

x\frac{dx}{dt} = - y\frac{dy}{dt}

where

\frac{dx}{dt} = Rate of change of displacement along the horizontal

\frac{dy}{dt} = Rate of change of displacement along the vertical

v_{x} = velocity along the x-axis.

v_{y} = velocity along the y-axis

xv_{x} = -yv_{y}

v_{y} = - 10\times \frac{1}{20} = - 0.5 ft/s

|v_{y}| = 0.5\ ft/s

Acceleration of the hay bale is given by the kinematic equation:

v_{y}^{2} = u_{y} + 2ay

(-0.5)^{2} =0 + 2ay

0.25 = 2ay

\frac{0.25}{2y} = a

a = \frac{0.25}{2\times 20} = 6.25\times 10^{- 3} ft/s^{2}

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3 years ago
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Gravity only determines the path in projectile motion
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3 years ago
A train whistle is heard at 300 Hz as the train approaches town. The train cuts its speed in half as it nears the station, and t
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To solve this problem we will apply the concepts related to the Doppler effect. The Doppler effect is the change in the perceived frequency of any wave movement when the emitter, or focus of waves, and the receiver, or observer, move relative to each other. Mathematically it can be described as,

f = f_0 (\frac{v_0}{v_0-v})

Here,

f_0 = Frequency of Source

v_s = Speed of sound

f = Frequency heard before slowing down

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So if the speed of the train after slowing down will be v/2, we can do a system equation of 2x2 at the two moments, then,

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Now the second expression will be,

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v = 22.12m/s

Therefore the speed of the train before and after slowing down is 22.12m/s

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