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Setler [38]
2 years ago
6

What do particulates in the atmosphere do?

Chemistry
1 answer:
MArishka [77]2 years ago
4 0
A or C but I think C
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When discussing acids and bases, any substance that accepts a proton, by definition, is considered
enot [183]
Any substance that accept a proton by definition is considered to be BRONSTED LOWRY BASE.
Bronsted Lowry defined acid and base on the basis of donating or accepting protons. In the Bronsted Lowry classification of acid and base, an acid is defined as a substance which donate proton while a base is defined as a substance which accept proton.
4 0
3 years ago
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A teacher wrote the following part of a balanced chemical equation: Cu+2AgNO 3 To show the conservation of matter in the chemica
Llana [10]
2, because there are 2 silver atoms on the left
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2 years ago
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Determine the number of significant figures in the measurement quantity: 2600. kg.
xxMikexx [17]

Answer:

2600 kg has 4 significant figures

Explanation:

Any different number to zero is a significant figure

For example, 1.8 → 2 significant figures

When you  have 0 in the middle of two numbers, we consider it as a significant number

For example, 3.02 → 3 significant figures

When you have 0 on the left in the measure, we do not consider as a sgnificant figures

For example 0.0010 → 2 significant figures (10)

3.0 → 2 significant figures (0 is on the right, not the left)

7 0
2 years ago
What is the percent of oxygen by mass in C2H402
Rom4ik [11]

Answer:

53.3 %.

Explanation: C2H4O2. = 2 * 12.011 + 4 * 1.008 + 2 * 15.999. = 60.052.

6 0
2 years ago
In an experiment, 16.8 g of k2so4 was dissolved in 1.00 kg of water to make a solution. the freezing point of the solution was m
Mashutka [201]
Answer is: V<span>an't Hoff factor (i) for this solution is 2,26.
</span>Change in freezing point from pure solvent to solution: ΔT =i · Kf · m.
<span>Kf - molal freezing-point depression constant for water is 1,86°C/m.
</span>m -  molality, moles of solute per kilogram of solvent.
n(K₂SO₄) = 16,8 g ÷ 174,25 g/mol
n(K₂SO₄) = 0,096 mol.
m(K₂SO₄) = 0,096 mol/kg.
ΔT = 0,405°C.
i = 0,405 ÷ (1,86 · 0,096)
i = 2,26.

8 0
3 years ago
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