All categories

3 years ago

If the temperature of an object is 335K,how would his be expressed on the celsius scale ?

Chemistry

2 answers:

lubasha [3.4K]3 years ago

4 0

Answer:

The temperature would be 62 °C

Explanation:

Knowing that:

T(°C)= T(K) -273.15 K

being:

°C: Celsius degrees

K: Kelvin

T: Temperature

We have that

T(°C)= 335 K - 273.15 K = 61.85 °C

IRISSAK [1]3 years ago

3 0

335K would be expressed as 61.85 degrees Celsius

You might be interested in

At an ACME plant in Scottsdale Arizonia methanol is produced commercially

patriot [66]

Answer:

thats nice to know i will send Wile E. Coyote there for his supplys

Explanation:

4 0

3 years ago

Convert .004569g to mg

algol [13]

Answer:

4.569 mg

:)))))))))))))))

4 0

3 years ago

Read 2 more answers

An object 5 millimeters high is located 15 millimeters in front of a plane mirror. How far from the mirror is the image located?

agasfer [191]

The correct answer for the question that is being presented above is this one: "D. 15 millimeters." An object 5 millimeters high is located 15 millimeters in front of a plane mirror. T<span>he image of the mirror is located 15 millimeters.</span>

8 0

4 years ago

what is the pH of a solution that results when 0.010mol HNO3 is added to 500.ml of a solution that is 0.10M in aqueous ammonia a

WARRIOR [948]

Answer : The

pH of a solution is, 8.56

Explanation : Given,

$K_b=1.8\times 10^{-5}$

Concentration of ammonia (base) = 0.10 M

Concentration of ammonium nitrate (salt) = 0.55 M

First we have to calculate the value of $pK_b$ .

The expression used for the calculation of $pK_b$ is,

$pK_b=-\log (K_b)$

Now put the value of $K_b$ in this expression, we get:

$pK_b=-\log (1.8\times 10^{-5})$

$pK_b=5-\log (1.8)$

$pK_b=4.7$

Now we have to calculate the pOH of buffer.

Using Henderson Hesselbach equation :

$pOH=pK_b+\log \frac{[Salt]}{[Base]}$

Now put all the given values in this expression, we get:

$pOH=4.7+\log (\frac{0.55}{0.10})$

$pOH=5.44$

The pOH of buffer is 5.44

Now we have to calculate the pH of a solution.

$pH+pOH=14\\\\pH+5.44=14\\\\pH=14-5.44\\\\pH=8.56$

Thus, the pH of a solution is, 8.56

8 0

3 years ago

The charge of the stable ion of P

Lady bird [3.3K]

Answer:

its charge could be negative three(-3)

6 0

3 years ago