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Illusion [34]
2 years ago
8

How the molecule’s properties affect the physical properties of a molecule

Chemistry
1 answer:
Lilit [14]2 years ago
8 0

The intermolecular forces, such as hydrogen bonds or van der Waals attractions, which draw one molecule to its neighbors, govern a substance's physical properties. Due to the relatively weak intermolecular forces of attraction, molecular substances typically take the form of gases, liquids, or low melting point solids.

<h3>How do the intermolecular forces affect physical properties?</h3>

The forces that bind two molecules together are known as intermolecular forces. Intermolecular forces have an impact on physical properties. Strong and weak forces both exist; the stronger the force, the more energy is needed to separate the molecules from one another. As intermolecular forces increase melting, boiling, and freezing points rise.

The following intermolecular forces are listed in order of strength:

  • Van der Waals dispersion forces
  • Van der Waals dipole-dipole interactions
  • Hydrogen bonding
  • Ionic bonds

It would take very little energy to separate two molecules if they are connected by van der Waals dispersion forces. On the other hand, it requires a lot more energy to separate two molecules that are joined together by ionic bonds.

To know more about molecules refer to: brainly.com/question/1819972

#SPJ1

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Answer:

Explanation:

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step 1:

we start by writing the reaction between iron and oxygen

We have this as:

\text{ Fe + O}_2

step 2:

Now, we want to predict the product as follows:

\text{ Fe + O}_2\text{ }\rightarrow Fe_2O_3

step 3:

We proceed to balance the chemical reaction as follows by ensuring that the number of elements moles on the reactant side is equal to the number of moles of the elements on the products side as follows:

\text{ 4Fe + 3O}_2\text{ }\rightarrow2Fe_2O_3

3 0
1 year ago
A sample of an unknown gas takes 222 s to diffuse through a porous plug at a given temperature. At the same temperature, N2(g) t
gulaghasi [49]

Answer:

\large \boxed{\text{45.1 g/mol}}

Explanation:

Graham’s Law applies to the diffusion of gases:

The rate of diffusion (r) of a gas is inversely proportional to the square root of its molar mass (M).

r \propto \dfrac{1}{\sqrt{M}}

If you have two gases, the ratio of their rates of diffusion is

\dfrac{r_{2}}{r_{1}} = \sqrt{\dfrac{M_{1}}{M_{2}}}

The time for diffusion is inversely proportional to the rate.

\dfrac{t_{2}}{t_{1}} = \sqrt{\dfrac{M_{2}}{M_{1}}}

Data:

t₂ = 222 s

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M₁ = 28.01

Calculation :

\begin{array}{rcl}\dfrac{222}{175} & = & \sqrt{\dfrac{M_{2}}{28.01}}\\\\1.269 & = & \sqrt{\dfrac{M_{2}}{28.01}}\\\\1.609 & = & \dfrac{M_{2}}{28.01}\\\\M_{2} & = & 1.609 \times 28.01\\ & = & \textbf{45.1 g/mol}\\\end{array}\\\text{The molar mass of the unknown gas is $\large \boxed{\textbf{45.1 g/mol}}$}

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3 years ago
a little kitten jumps from a tree and hits the ground 2.6 seconds later.with this information calculate the cat's velocity right
Harlamova29_29 [7]
The initial velocity is equal zero 
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3 0
3 years ago
Pls help thank you I really need
Fofino [41]

Answer:

A

Explanation:

8 0
3 years ago
Read 2 more answers
how many grams of ammonium carbonate are needed to decompose in order to produce 6.52 g of carbon dioxide?
defon

Answer:

<u>= 14.24g of </u>(NH4)_{2}CO_{3}<u> is required.</u>

Explanation:

Reaction equation:

(NH4)_{2}CO_{3} → 2NH_{3} + CO_{2} + H_{2} O

Mole ratio of ammonium carbonate to carbon dioxide is 1:1

1 mole of CO2 - 44g

?? mole of CO2 - 6.52g

= 6.52/44 = 0.148 moles was produced from this experiment.

Therefore, if 1 mole of (NH4)_{2}CO_{3} - 96.09 g

0.148 mol of (NH4)_{2}CO_{3} --  ?? g

=0.148 × 96.09

<u>= 14.24g of </u>(NH4)_{2}CO_{3}<u> is required.</u>

5 0
3 years ago
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