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2 years ago

Which binary molecular compound includes an element with five atoms of one element?

Chemistry

1 answer:

uranmaximum [27]2 years ago

6 0

Answer:

For example, N2O4 is referred to as dinitrogen tetroxide, not dinitrogen tetraoxide, and CO is called carbon monoxide, not carbon monooxide.

...

Binary molecular (covalent) compounds.

Prefixes used in chemical nomenclature

prefix number of atoms

tetra- 4

penta- 5

hexa- 6

Explanation:

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A solution is a homogenous mixture of solute and solvent. There are different types of solutions. A carbonated drink is an examp

goblinko [34]

Answer:

A.) Gases are readily soluble in water at higher temperatures: FALSE

B.) Carbon dioxide gas will be less soluble in water when the partial pressure is low: TRUE

C.) Zinc sulfate is soluble in water: TRUE

D.) Propanol and heptane are miscible: FALSE

E.) Table salt dissolves in water to form a solution: TRUE

Explanation:

The answer choices are:

A.) Gases are readily soluble in water at higher temperatures.
B.) Carbon dioxide gas will be less soluble in water when the partial pressure is low.
C.) Zinc sulfate is soluble in water.
D.) Propanol and heptane are miscible.
E.) Table salt dissolves in water to form a solution.

<h2>Solution</h2>

Let's see every statement

A.) Gases are readily soluble in water at higher temperatures.

This is false. At higher temperature, the gas molecules will have higher kinetic energy, meaning that they will move faster and escape more easily from the liquid phase. Thus, gases are less soluble at higher temperatures.

B.) Carbon dioxide gas will be less soluble in water when the partial pressure is low.

This is TRUE.

HIgher pressures "push" the gas molecules into the liquid phase. When more molecules get dissolved the pressure is partially relieved.

This relation is stated by Henry's Law: the solubility of gases in liquids is directly proportional to the pressure of the gases above the surface of the solution. Thus, carbon dioxide will me less soluble in water when the pressure is low.

C.) Zinc sulfate is soluble in water.

This is TRUE.

You must resort to the rules of solubility or search the properties of this salt.

Th solubility rules state that most sulfates are soluble in water. Exceptions are sulfates of Ag⁺,Ca²⁺, Sr²⁺, Ba²⁺, Hg²⁺, and Pb²⁺. Thus, you can expect that zinc sulfate is soluble in water.

D.) Propanol and heptane are miscible.

This is false.

Propanol is a polar compound. It is miscible with water because water is polar too. Heptane is not polar. Thus, following the rule that "like dissolves like" propanol and heptane are not miscible.

E.) Table salt dissolves in water to form a solution.

This is TRUE.

This is a classical example of an ionic compound (sodium chloride) that is soluble in water (a polar solvent), showing the rule that polar solvents dissolve polar and ionic compounds.

It is also an everyday fact: rice, for instance, absorbs salt from water because the salt is dissolved in the water.

3 0

3 years ago

PLEASE HELP AND THANKS

Kamila [148]

Answer:

torque =force*distance

4 0

3 years ago

The pot shown in the picture is made of two different metals. Why is the handle made of a different metal than the rest of the p

sertanlavr [38]

The rest of the bot needs to be able to heat up to cook ur food but the handles should be cooler so u can touch them

8 0

3 years ago

Read 2 more answers

Complete the dissociation reaction and the corresponding Ka equilibrium expression for each of the following acids in water. (Ty

anastassius [24]

Answer :

(A) The dissociation reaction of $HC_2H_3O_2$ will be:

$HC_2H_3O_2(aq)\rightleftharpoons H^+(aq)+C_2H_3O_2^-(aq)$

The equilibrium expression :

$K_a=\frac{[H^+][C_2H_3O_2^-]}{[HC_2H_3O_2]}$

(B) The dissociation reaction of $Co(H_2O)_6^{3+}$ will be:

$Co(H_2O)_6^{3+}(aq)\rightleftharpoons H^+(aq)+Co(H_2O)_5(OH)^{2+}(aq)$

The equilibrium expression :

$K_a=\frac{[H^+][Co(H_2O)_5(OH)^{2+}]}{[Co(H_2O)_6^{3+}]}$

(C) The dissociation reaction of $CH_3NH_3^+$ will be:

$CH_3NH_3^+(aq)\rightleftharpoons H^+(aq)+CH_3NH_2(aq)$

The equilibrium expression :

$K_a=\frac{[H^+][CH_3NH_2]}{[CH_3NH_3^+]}$

Explanation :

Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

The equilibrium expression for the reaction is determined by multiplying the concentrations of products and divided by the concentrations of the reactants and each concentration is raised to the power that is equal to the coefficient in the balanced reaction.

As we know that the concentrations of pure solids and liquids are constant that is they do not change. Thus, they are not included in the equilibrium expression.

(A) The dissociation reaction of $HC_2H_3O_2$ will be:

$HC_2H_3O_2(aq)\rightleftharpoons H^+(aq)+C_2H_3O_2^-(aq)$

The equilibrium expression of $HC_2H_3O_2$ will be:

$K_a=\frac{[H^+][C_2H_3O_2^-]}{[HC_2H_3O_2]}$

(B) The dissociation reaction of $Co(H_2O)_6^{3+}$ will be:

$Co(H_2O)_6^{3+}(aq)\rightleftharpoons H^+(aq)+Co(H_2O)_5(OH)^{2+}(aq)$

The equilibrium expression of $Co(H_2O)_6^{3+}$ will be:

$K_a=\frac{[H^+][Co(H_2O)_5(OH)^{2+}]}{[Co(H_2O)_6^{3+}]}$

(C) The dissociation reaction of $CH_3NH_3^+$ will be:

$CH_3NH_3^+(aq)\rightleftharpoons H^+(aq)+CH_3NH_2(aq)$

The equilibrium expression of $CH_3NH_3^+$ will be:

$K_a=\frac{[H^+][CH_3NH_2]}{[CH_3NH_3^+]}$

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3 years ago

A stock solution containing Mn2 ions was prepared by dissolving 1.269 g pure manganese metal in nitric acid and diluting to a fi

SOVA2 [1]

Answer:

Explanation:

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3 years ago