Answer:
464.29mL de solvente y 35.71mL de ácido nítrico concentrado deben agregarse.
Explanation:
El ácido nítrico concentrado viene al 70% v/v por temas de estabilidad. El volumen de ácido nítrico que se debe agregar si se quieren hace 500mL al 5% de HNO3 es:
500mL * (5mL / 100mL) = 25mL de ácido nítrico se deben agregar.
Como el ácido nítrico está al 70%:
25mL ácido nítrico * (100mL / 70mL ácido nítrico) = 35.71mL de ácido nítrico concentrado deben agregarse.
Y el volumen de solvente debe ser:
500mL - 35.71mL = 464.29mL
Answer:
<em>2.085 x 10^-20 J</em>
<em></em>
Explanation:
minimum energy required to produce photoelectric effect in chromium is given as hf = 7.21 x 10^-19 J
The work function of chromium Ф = 4.37 eV = 7.00151 x 10^-19 J
The minimum energy required to eject an electron from from a chromium metal E = ?
From E = hf - Ф
substituting values, we have
E = (7.21 x 10^-19) - (7.00151 x 10^-19)
E = <em>2.085 x 10^-20 J</em>
When we balance the given equation
SF₆(g) + SO₃(g) → SO₂F₂(g)
We will get
SF₆(g) + 2SO₃(g) → 3SO₂F₂(g)
Solution:
Balancing the given equaation
SF₆(g) + SO₃(g) → SO₂F₂(g)
We have to balance the given number of O
SF₆(g) + 2SO₃(g) → 3SO₂F₂(g)
We get balanced equation
SF₆(g) + 2SO₃(g) → 3SO₂F₂(g)
The reaction quotient will be
Qc = [product] / [reactant]
Qc = [SO₂F₂(g)] / [SF₆(g) + SO₃(g)]
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Answer:
- FeS
- MnO₂
- Al₂S₃
Explanation:
<u>1) Iron + Sulphur = ?</u>
→ Iron sulfide
<u>2) Manganese + Oxygen = ?</u>
→ Manganese dioxide
<u>3) Aluminium + Sulphur = ?</u>
→ Aluminium sulfide
