Question

A roller coaster has a 100.0 kg cart at the top of a 22.0 m ramp. As it goes down the ramp, it change 800.0 joules of energy to heat due to friction. What will the kinetic energy be at the bottom of the ramp?
a. 800 J
b. 100 J
c. 0 J
d. 20760 J
e. 22360 J

Answer 1

Answer:

d.20760 J

Explanation:

We are given that

Mass of cart=m=100 kg

At the top,h=22 m

Amount of energy convert into heat due to friction=E=800 J

We have to find the kinetic energy at the bottom of the ramp.

Potential energy drop=mgh=$100\times 9.8\times 22=21560 J$

Kinetic energy at the bottom=Potential energy drop-energy lost due to friction

Kinetic energy at the bottom =(21560-800) J

Kinetic energy at the bottom=20760 J

Hence, the kinetic energy at the bottom of the ramp=20760 J

d.20760 J