A roller coaster has a 100.0 kg cart at the top of a 22.0 m ramp. As it goes down the ramp, it change 800.0 joules of energy to
1 answer:
Answer:
d.20760 J
Explanation:
We are given that
Mass of cart=m=100 kg
At the top,h=22 m
Amount of energy convert into heat due to friction=E=800 J
We have to find the kinetic energy at the bottom of the ramp.
Potential energy drop=mgh=
Kinetic energy at the bottom=Potential energy drop-energy lost due to friction
Kinetic energy at the bottom =(21560-800) J
Kinetic energy at the bottom=20760 J
Hence, the kinetic energy at the bottom of the ramp=20760 J
d.20760 J
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Answer:
Approximate escape speed = 45.3 km/s
Explanation:
Escape speed
Here we have
Gravitational constant = G = 6.67 × 10⁻¹¹ m³ kg⁻¹ s⁻²
R = 1 AU = 1.496 × 10¹¹ m
M = 2.3 × 10³⁰ kg
Substituting
Approximate escape speed = 45.3 km/s
Answer:
<em>The final speed of the second package is twice as much as the final speed of the first package.</em>
Explanation:
<u>Free Fall Motion</u>
If an object is dropped in the air, it starts a vertical movement with an acceleration equal to g=9.8 m/s^2. The speed of the object after a time t is:
And the distance traveled downwards is:
If we know the height at which the object was dropped, we can calculate the time it takes to reach the ground by solving the last equation for t:
Replacing into the first equation:
Rationalizing:
Let's call v1 the final speed of the package dropped from a height H. Thus:
Let v2 be the final speed of the package dropped from a height 4H. Thus:
Taking out the square root of 4:
Dividing v2/v1 we can compare the final speeds:
Simplifying:
The final speed of the second package is twice as much as the final speed of the first package.