Answer:
1: Killing a specific gene.
2: augmentation of a gene.
3: Inserting a new dominant gene.
Explanation:
Answer: to see if the matter is a compound, mixture, or element.
Explanation:
can you please help with my most recent question :)
The formula for Cs and S is Cs₂S.
For Cs and S,
Ions formed will be Cs⁺ and S²⁻
As cesium belongs to group 1A and sulfur belongs to group 6A. Therefore, the condensed electronic configuration is -
For Cs is [Xe} 6s¹ and for S is [Ne] 3s²3p⁴.
Cs have 1 valence electron and S have 6 valence electrons.
Hence to attain a stable electronic configuration, both two Cs atoms lose one electron and form Cs⁺ and these two electrons will be accepted by one S atom to form S²⁻.
Therefore the formula for the compound is Cs₂S as Cs donate 1 electron and S will accept 2 electrons from Cs.
The formula is Cs₂S.
To learn more about electronic configuration, visit: brainly.com/question/15051483
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Answer: here is a description of what they look like since I cannot see the diagram.
Mitochondria- wavy line
Ribosomes- little dots
Chromosome- X
Nucleus- Circle with bite taken out of it
Endoplasm- Bubble
Nuclear membrane- Outer layer/bubble
Golgi-wavy circle thing
Vacuole- Bigger circle (but not nucleus)
Cytoplasm- its the jelly on the inside
Cell wall- only in plant cells, looks like a box
Cell membrane- The outmost part of the animal cell, the barrier.
I sure hope this helps!!!
Answer:
Depression in freezing point = 2 X 1.853 X 0.25 = 0.9625
Thus this will be the difference between the freezing point of pure water and the solution.
Explanation:
On adding any non volatile solute to a solvent its boiling point increases and its freezing point decreases [these are two of the four colligative properties].
The depression in freezing point is related to molality of solution as:
ΔTf
where
ΔTf= depression in freezing point
Kf= cryoscopic constant of water = 1.853 K. kg/mol.
i = Van't Hoff factor = 2 ( for KCl)
molality = 
moles of solute = mass / molarmass = 4.66 / 74.55 =0.0625
mass of solvent = mass of solution (almost)
considering the density of solution to be 1g/mL
mass of solvent = 250 grams = 0.250 Kg
molality = 
Putting values
depression in freezing point = 2 X 1.853 X 0.25 = 0.9625
Thus this will be the difference between the freezing point of pure water and the solution.
