8. How many moles are in 3.01 X 10^24 of oxygen atoms?

Find the mass of 2.16 × 1023 molecules H2S.<br> Answer in units of g.

worty [1.4K]

Answer:

Mass = 12.276 g

Explanation:

Given data:

Number of molecules of H₂S = 2.16 × 10²³

Mass in gram = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

Number of moles of H₂S:

2.16 × 10²³ molecules × 1 mole /6.022 × 10²³ molecules

0.36 moles

Mass = number of moles × molar mass

Mass = 0.36 mol × 34.1 g/mol

Mass = 12.276 g

7 0

3 years ago

What is the wavelength of light emitted when the electron in a hydrogen atom undergoes transition from an energy level with n =

Lady bird [3.3K]

Answer:

$4.86\times10^{-7}\ \text{m}$

Explanation:

R = Rydberg constant = $1.09677583\times 10^7\ \text{m}^{-1}$

$n_1$ = Principal quantum number of an energy level = 2

$n_2$ = Principal quantum number of an energy level for the atomic electron transition = 4

Wavelength is given by the Rydberg formula

$\lambda^{-1}=R\left(\dfrac{1}{n_1^2}-\dfrac{1}{n_2^2}\right)\\\Rightarrow \lambda^{-1}=1.09677583\times 10^7\left(\dfrac{1}{2^2}-\dfrac{1}{4^2}\right)\\\Rightarrow \lambda=\left(1.09677583\times 10^7\left(\dfrac{1}{2^2}-\dfrac{1}{4^2}\right)\right)^{-1}\\\Rightarrow \lambda=4.86\times10^{-7}\ \text{m}$

The wavelength of the light emitted is $4.86\times10^{-7}\ \text{m}$ .

6 0

2 years ago

What are Free Radicals ?

DENIUS [597]

Answer:

an uncharged molecule (typically highly reactive and short-lived) having an unpaired valency electron.

4 0

2 years ago

Read 2 more answers

Genes determine I. the function of a protein II. the length of a protein III. the shape of a protein IV. the sequence of amino a

Schach [20]

I believe it is the sequence of amino acids in a protein

7 0

3 years ago

Osmium metal, the densest element, has a density of 22.6 g/mL, while hydrogen, the least dense element, has a density of 8.99 e-

KengaRu [80]

Answer:

1. Volume of osmium = 0.044 mL

2. Volume of Hydrogen = 11123.47 mL

3. Osmium is 251390 times denser than hydrogen

Explanation:

From the question given above, the following data were obtained:

Density of osmium = 22.6 g/mL

Density of Hydrogen = 8.99×10¯⁵ g/mL

Mass of osmium = 1 g

Mass of Hydrogen = 1 g

1. Determination of the Volume of osmium.

Density of osmium = 22.6 g/mL

Mass of osmium = 1 g

Volume of osmium =?

Density = mass /volume

22.6 = 1 / volume

Cross multiply

22.6 × volume = 1

Divide both side by 22.6

Volume = 1 / 22.6

Volume of osmium = 0.044 mL

2. Determination of the Volume of Hydrogen.

Density of osmium = 8.99×10¯⁵ g/mL

Mass of osmium = 1 g

Volume of osmium =?

Density = mass /volume

8.99×10¯⁵ = 1 / volume

Cross multiply

8.99×10¯⁵ × volume = 1

Divide both side by 8.99×10¯⁵

Volume = 1 / 8.99×10¯⁵

Volume of Hydrogen = 11123.47 mL

3. Determination of the number of times osmium is denser than hydrogen.

Density of osmium (Dₒ) = 22.6 g/mL

Density of Hydrogen (Dₕ) = 8.99×10¯⁵ g/mL

Dₒ / Dₕ = 22.6 / 8.99×10¯⁵

Dₒ / Dₕ = 251390

Cross multiply

Dₒ = 251390 × Dₕ

Thus, osmium is 251390 times denser than hydrogen.

5 0

2 years ago