O: palisade layer and please answer the question I am gonna post right now pleaseeee
Answer:
(e) -6.1 J/K
Explanation:
Step 1: Given data
- Heat of fusion of ice (ΔH°fus): 333.5 J/g
Step 2: Calculate the heat (Qfreezing) required to freeze 5.0 g of water
We will use the following expression.
Qfreezing = -ΔH°fus × m
Qfreezing = -333.5 J/g × 5.0 g = -1.7 × 10³ J
Step 3: Calculate the entropy change (ΔS°) at 0 °C (273.15 K) and 1 atm
We will use the following expression.
ΔS° = Qfreezing/T
ΔS° = -1.7 × 10³ J/273.15 K = -6.1 J/K
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Answer:
108.3g
Explanation:
Given parameters:
Volume of solution = 570mm = 0.57L (1000mm = 1L)
Molarity of solution = 2M
Unknown
Mass of MgCl₂
Solution
We first find the number of moles in the given concentration of magnessium chloride using the expression below:
Number of moles of MgCl₂= Molarity x volume = 2 x 0.57 = 1.14moles
Using this known moles, we can the unknown mass of MgCl₂ the technician would require:
Mass of MgCl₂ required = number of moles of MgCl₂ x molar mass
Molar mass of MgCl₂:
Atomic mass of Cl = 35.5g
Atomic mass of Mg = 24g
MgCl₂ = 24 + (35.5x2) = 95gmol⁻¹
Mass of MgCl₂ required = 1.14mole x 95gmole⁻¹ = 108.3g
