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leonid [27]
3 years ago
8

A car travels 136 miles using 7 gallons of gas. At that rate, how far can the car travel using 42 gallons of gas?

Mathematics
2 answers:
Zanzabum3 years ago
5 0

Answer:

816 miles

Step-by-step explanation:

136miles/7 g =19.43

19.43 x 42 ≅ 816.06

or

136/7 = X/42

solve for X

42/7 =6, then 136 x6= 816

x = 816 miles

muminat3 years ago
4 0

Answer:

in 136 miles=7 gallons

?=42 gallon

= 136=7

?=42

cross multiply

136×42=5,712

=5,712÷7=816

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Over the course of 6 days Tonda ran 17.22 miles She ran the same distance each day How far did Tonga run each day ?
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Work Progress: 17.22mile/6 days = 2.87

Tonda ran 2.87 miles each day.

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Fiona was thinking of a number. Fiona doubles it and adds 5.1 to get an answer of 11.5. Form an equation with x? Whats the answe
saveliy_v [14]

Answer:

3.2

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N is an integer.<br> Write the values of n such that -15 &lt; 3 ≤ 6<br><br> Help please ❤️❤️
Alex17521 [72]

Answer:

-4,-3,-2,-1,0,1

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-15<3n

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-5<n<2.

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3 years ago
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Suppose we have 3 cards identical in form except that both sides of the first card are colored red, both sides of the second car
Nikolay [14]

Answer:

probability that the other side is colored black if the upper side of the chosen card is colored red = 1/3

Step-by-step explanation:

First of all;

Let B1 be the event that the card with two red sides is selected

Let B2 be the event that the

card with two black sides is selected

Let B3 be the event that the card with one red side and one black side is

selected

Let A be the event that the upper side of the selected card (when put down on the ground)

is red.

Now, from the question;

P(B3) = ⅓

P(A|B3) = ½

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P(A|B1) = 1

P(B2) = ⅓

P(A|B2)) = 0

(P(B3) = ⅓

P(A|B3) = ½

Now, we want to find the probability that the other side is colored black if the upper side of the chosen card is colored red. This probability is; P(B3|A). Thus, from the Bayes’ formula, it follows that;

P(B3|A) = [P(B3)•P(A|B3)]/[(P(B1)•P(A|B1)) + (P(B2)•P(A|B2)) + (P(B3)•P(A|B3))]

Thus;

P(B3|A) = [⅓×½]/[(⅓×1) + (⅓•0) + (⅓×½)]

P(B3|A) = (1/6)/(⅓ + 0 + 1/6)

P(B3|A) = (1/6)/(1/2)

P(B3|A) = 1/3

5 0
3 years ago
The sum of 5 consecutive integers is 265. What is the fifth number in this sequence?
son4ous [18]
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3 years ago
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