Work Progress: 17.22mile/6 days = 2.87
Tonda ran 2.87 miles each day.
Answer:
3.2
Step-by-step explanation:
11.5 - 5.1 = 6.4
6.4 ÷ 2 = 3.2
Answer:
-4,-3,-2,-1,0,1
Step-by-step explanation:
First, doublepound and simplify it.
-15<3n
3n<6
Solve:
-5<n
n<2
Compound:
-5<n<2.
So the values are -4,-3,-2,-1,0,1
Hope this helps plz hit the crown :D
Answer:
probability that the other side is colored black if the upper side of the chosen card is colored red = 1/3
Step-by-step explanation:
First of all;
Let B1 be the event that the card with two red sides is selected
Let B2 be the event that the
card with two black sides is selected
Let B3 be the event that the card with one red side and one black side is
selected
Let A be the event that the upper side of the selected card (when put down on the ground)
is red.
Now, from the question;
P(B3) = ⅓
P(A|B3) = ½
P(B1) = ⅓
P(A|B1) = 1
P(B2) = ⅓
P(A|B2)) = 0
(P(B3) = ⅓
P(A|B3) = ½
Now, we want to find the probability that the other side is colored black if the upper side of the chosen card is colored red. This probability is; P(B3|A). Thus, from the Bayes’ formula, it follows that;
P(B3|A) = [P(B3)•P(A|B3)]/[(P(B1)•P(A|B1)) + (P(B2)•P(A|B2)) + (P(B3)•P(A|B3))]
Thus;
P(B3|A) = [⅓×½]/[(⅓×1) + (⅓•0) + (⅓×½)]
P(B3|A) = (1/6)/(⅓ + 0 + 1/6)
P(B3|A) = (1/6)/(1/2)
P(B3|A) = 1/3
Five consecutive integers are:
n, n+1, n+2, n+3, n+4 the sum of which is:
5n+10=265 subtract 10 from both sides
5n=255, divide both sides by 5
n=51
Our fifth number was n+4 so the fifth number is 55
