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leonid [27]
3 years ago
8

A car travels 136 miles using 7 gallons of gas. At that rate, how far can the car travel using 42 gallons of gas?

Mathematics
2 answers:
Zanzabum3 years ago
5 0

Answer:

816 miles

Step-by-step explanation:

136miles/7 g =19.43

19.43 x 42 ≅ 816.06

or

136/7 = X/42

solve for X

42/7 =6, then 136 x6= 816

x = 816 miles

muminat3 years ago
4 0

Answer:

in 136 miles=7 gallons

?=42 gallon

= 136=7

?=42

cross multiply

136×42=5,712

=5,712÷7=816

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Angle A is 37 degrees, Angle B is 82 degrees, Angle C is 61 degrees

Step-by-step explanation:

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180 - 143 = 37

All angles add up to 180.

37 + 61 = 98

180 - 98 = 82

Angle B is 82 degrees.

Hope this helped. :)

7 0
3 years ago
Rob owes Debra $36 and pays her 1/3 of what he owes. How much does he now owe?
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Answer:

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3 0
3 years ago
Find the surface area of x^2+y^2+z^2=9 that lies above the cone z= sqrt(x^@+y^2)
Mashcka [7]
The cone equation gives

z=\sqrt{x^2+y^2}\implies z^2=x^2+y^2

which means that the intersection of the cone and sphere occurs at

x^2+y^2+(x^2+y^2)=9\implies x^2+y^2=\dfrac92

i.e. along the vertical cylinder of radius \dfrac3{\sqrt2} when z=\dfrac3{\sqrt2}.

We can parameterize the spherical cap in spherical coordinates by

\mathbf r(\theta,\varphi)=\langle3\cos\theta\sin\varphi,3\sin\theta\sin\varphi,3\cos\varphi\right\rangle

where 0\le\theta\le2\pi and 0\le\varphi\le\dfrac\pi4, which follows from the fact that the radius of the sphere is 3 and the height at which the sphere and cone intersect is \dfrac3{\sqrt2}. So the angle between the vertical line through the origin and any line through the origin normal to the sphere along the cone's surface is

\varphi=\cos^{-1}\left(\dfrac{\frac3{\sqrt2}}3\right)=\cos^{-1}\left(\dfrac1{\sqrt2}\right)=\dfrac\pi4

Now the surface area of the cap is given by the surface integral,

\displaystyle\iint_{\text{cap}}\mathrm dS=\int_{\theta=0}^{\theta=2\pi}\int_{\varphi=0}^{\varphi=\pi/4}\|\mathbf r_u\times\mathbf r_v\|\,\mathrm dv\,\mathrm du
=\displaystyle\int_{u=0}^{u=2\pi}\int_{\varphi=0}^{\varphi=\pi/4}9\sin v\,\mathrm dv\,\mathrm du
=-18\pi\cos v\bigg|_{v=0}^{v=\pi/4}
=18\pi\left(1-\dfrac1{\sqrt2}\right)
=9(2-\sqrt2)\pi
3 0
2 years ago
Monday: 10 apples and 5 bananas cost £4.20 Friday: 8 apples and 10 bananas cost £5.40 Find the cost of each - with an explanatio
motikmotik

Answer:

An apple costs £0.25

A banana costs £0.34

Step-by-step explanation:

Let a be apples and b be bananas.

10a+5b=4.2

8a+10b=5.4

Solve for a:

10a+5b=4.2

<em>Subtract 5b from both sides</em>

10a=4.2-5b

<em>Subtract 4.2 from both sides</em>

10a-4.2= -5b

<em>Multiply both sides by -1</em>

-10a+4.2=5b

8a+10b=5.4

<em>Subtract 10b from both sides</em>

8a=5.4-10b

<em>Subtract 5.4 from both sides</em>

8a-5.4= -10b

<em>Multiply both sides by -1</em>

-8a+5.4= 10b

<em>Divide both sides by 2</em>

-4a+2.7=5b

<u>Combine equations:</u>

-4a+2.7= -10a+4.2

<em>Add 10a to both sides</em>

6a+2.7=4.2

<em>Subtract 2.7 from both sides</em>

6a=1.5

<em>Divide both sides by 6</em>

a=0.25

An apple costs £0.25

Solve for b:

10a+5b=4.2

<em>Subtract 10a from both sides</em>

5b= -10a+4.2

<em>Subtract 4.2 from both sides</em>

5b-4.2= -10a

<em>Multiply both sides by -1</em>

-5b+4.2=10a

8a+10b=5.4

<em>Subtract 8a from both sides</em>

10b= -8a+5.4

<em>Subtract 5.4 from both sides</em>

10b-5.4= -8a

<em>Divide both sides by 4</em>

2.5b-1.35= -2a

Multiply both sides by 5

12.5b-6.75= -10a

<em>Multiply both sides by -1</em>

-12.5b+6.75=10a

<u>Combine equations:</u>

-12.5b+6.75= -5b+4.2

<em>Add 12.5b to both sides</em>

6.75=7.5b+4.2

<em>Subtract 4.2 from both sides</em>

2.55=7.5b

7.5b=2.55

<em>Divide both sides by 7.5</em>

b=0.34

A banana costs £0.34

If you would like to check and see if it is true, (I already checked, it is) you can use the formulas I gave at the start of the explanation.

10a+5b=4.2

8a+10b=5.4

a=0.25

b=0.34

3 0
3 years ago
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