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Vinil7 [7]
3 years ago
15

Explain how Law 1 applies to the image to the left.

Physics
2 answers:
Margarita [4]3 years ago
6 0

Answer:

12?

Explanation:

alisha [4.7K]3 years ago
3 0

Answer:

12

Explanation:

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What type of energy does a stove use to convert into heat
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This Is What I Found<span>(Non-electric stoves and ovens use gas energy, a chemical energy. This is then transformed into heat.) What types of energy does a computer convert electricity into? (Light, sound, motion, and heat.)    I'm Not Taking Credit For It, Because I Didn't Come Up With That Answer.</span>
4 0
3 years ago
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A crane lifts an air conditioner to the top of a building. If the building is 12 m high, and the air conditioner has a mass of 2
Pepsi [2]

Work needed = 23,520 J

<h3> Further explanation </h3>

Given

height = 12 m

mass = 200 kg

Required

work needed by the crane

Solution

Work is the transfer of energy caused by the force acting on a moving object  

Work is the product of force with the displacement of objects.  

Can be formulated  

W = F x d  

W = Work, J, Nm  

F = Force, N  

d = distance, m  

F = m x g

Input the value :

W = mgd

W = 200 kg x 9.8 m/s²x12 m

W = 23520 J

8 0
2 years ago
radio waves are electromagnetic waves that travel at the speed of light 300 000 kilometers per second what is the wave length of
Anarel [89]
<h2>Answer:</h2>

<h2>3m</h2>

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<h2>Hope this helps you ❤️</h2>

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3 0
3 years ago
Using your best estimates, how many times would you have to slap a 1 kg rotisserie chicken in order to cook it? You can assume t
FromTheMoon [43]

Answer:

n= 16021.03 slaps

Explanation:

Using law of Energy conservation

E_{thermal}= Kinetic energy of hand

⇒mc\Delta T= n\frac{1}{2}m_hv_h^2

m_h= mass of the hand = 0.4 kg

v_h= velocity of the hand = 10 m/s

n= number of slaps

c= 4180 J/Kg °C

m= mass of chicken = 1 kg

Assuming all the energy of hand goes into chicken

Given Ti=0°C and T_f= 170 F= 76.66°C

Now putting the values in above equation to get n

1\times4180(76.66)= n\frac{1}{2}0.4\times10^2

n= 16021.03 slaps

8 0
3 years ago
The charge that passes a cross-sectional area A=10-4 m2 varies with time according
Anarel [89]

Answer:

Current = dQ/dt

or I = dQ/dt

Where I represents current.

Which is the rate of flow of charge.

Q=4 + 2t + t²

dQ/dt = 2 + 2t --- This is the relation that gives the instantaneous current.

At time t=2sec

dQ/dt = I = 2 + 2t

= 2 + 2(2)

=2 + 4

= 6A.

6 0
3 years ago
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