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Darina [25.2K]
2 years ago
14

Electricity The power P, in watts, that a circular solar cell produces and radius of the cell in centimeters are related by the

square root equation
r =   \sqrt{ \frac{p  }{0.02\pi} }
about how much power is produced by a cell with a radius of 12 cm?​
Physics
1 answer:
gavmur [86]2 years ago
5 0

Answer:

9.05 W

Explanation:

The given formula is r=\sqrt {\frac {P}{0.02\pi}} where r is in centimeters and P is in Watts

Making Power, P the subject from the above formula

P=0.02\pi r^{2}

Substituting r with 12 cm then

P=0.02\pi 12^{2}=
9.047786842  W\approx 9.05 W

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3 years ago
Which pair does NOT have an electric force between them?.
viva [34]

Two neutral objects will not have any electric force of attraction or repulsion between them.

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2 years ago
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Before colliding, the momentum of block A is -100 kg*m/, and block B is -150 kg*m/s. After, block A has a momentum -200 kg*m/s.
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Answer:

Momentum of block B after collision =-50\ kg\ ms^{-1}

Explanation:

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Before collision:

Momentum of block A = p_{A1}= -100\ kg\ ms^{-1}

Momentum of block B = p_{B1}= -150\ kg\ ms^{-1}

After collision:

Momentum of block A = p_{A2}= -200\ kg\ ms^{-1}

Applying law of conservation of momentum to find momentum of block B after collision p_{B2}.

p_{A1}+p_{B1}=p_{A2}+p_{B2}

Plugging in the given values and simplifying.

-100-150=-200+p_{B2}

-250=-200+p_{B2}

Adding 200 to both sides.

200-250=-200+p_{B2}+200

-50=p_{B2}

∴ p_{B2}=-50\ kg\ ms^{-1}

Momentum of block B after collision =-50\ kg\ ms^{-1}

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Answer:

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