anything that turns red litmus paper to blue it is an acid and vice versa is true
The question is incomplete, here is the complete question:
A chemist adds 370.0 mL of a 2.25 M iron(III) bromide solution to a reaction flask. Calculate the mass in grams of iron(III) bromide the chemist has added to the flask. Round your answer to 3 significant digits
<u>Answer:</u> The mass of iron (III) bromide is 246. grams
<u>Explanation:</u>
To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

We are given:
Molarity of solution = 2.25 M
Molar mass of iron (III) bromide = 295.6 g/mol
Volume of solution = 370.0 mL
Putting values in above equation, we get:

Hence, the mass of iron (III) bromide is 246. grams
Answer:
activity series is a list of substances ranked in order of relative reactivity.
For example, magnesium metal can displace hydrogen ions from solution. So magnesium is more reactive than hydrogen:
Mg(s) + 2H⁺(aq) → H₂(g) + Mg²⁺(aq)
Zinc metal can also displace hydrogen ions from solution:
Zn(s) + 2H⁺(aq) → H₂(g) + Zn²⁺(aq)
so zinc is also more active than hydrogen.
But magnesium metal can displace zinc ions from solution:
Mg(s) + Zn²⁺(aq) → Zn(s) + Mg²⁺(aq)
so magnesium is more active than zinc.
The activity series including these elements would be Mg > Zn > H.
Chemists have built up a complete activity series in a similar way.
The most active metals are at the top of the table; the least active are at the bottom.
Any metal that is higher in the series will displace a metal that is below it in a
Answer:
The moon's surface has been struck with other objects.
Explanation:
Answer 1 - Craters are not a sign of alien life as there is nothing directly showing the crater's are not natural phenomena.
Answer 2 - Craters are (normally) produced by the impact force of a foreign object that is moving quickly and collides with an object of larger size.
Answer 3 - Volcanos form mountains and magma tubes, not craters.
Answer 4 - The formation of mountains does not relate to craters in any meaningful way.
The compound is Tin(IV) bromide