3 years ago

Answer 4 and I’ll give brainlist

Physics

1 answer:

Sedbober [7]3 years ago

4 0

Answer:

Answer C

Explanation:

The closer two masses are, the greater the gravity force between them.

This is shown in the formula

Fg = GMm/R²

Smaller distance R means greater force Fg

You might be interested in

An individual motor disconnect must be in sight of the motor controller and must disconnect the controller. NEC definition of in

VashaNatasha [74]

Answer: a) 50

Explanation:

This implies that the controller must be visible at not more than 50ft which is 15m

4 0

3 years ago

How much work, in Joules. is done when a pressure of 95.000 Pa changes a volume from 15 ma to 43 m2?

gayaneshka [121]

Answer:

-2.66 kJ

Explanation:

At constant pressure, work done is:

W = -P ΔV

W = -(95.000 Pa) (43 m² − 15 m²)

W = -2660 J

W = -2.66 kJ

5 0

4 years ago

Three moles of an ideal gas are taken around the eyele acb shown in Fig.For this gas Co-29.2J/mol-K.Process ac is at constant pr

Scorpion4ik [409]

For three moles of an ideal gas are taken around the eye, the total work for the cycle is mathematically given as

Wt=1945.475J

<h3>What is the total work F for the cycle.(R=8.31J/molK)?</h3>

Generally, the equation for work is mathematically given as

Wt=wac+Wc+Wba

Therefore

Wac=Pa(Vc-Va)=nR(Tc-Ta)

Wac=3(8.314*192)

Wac=4788.864J

Wcb=P1v1-p2v2/v-1

Wcb-3*8.34*108/0.4

Wcb=-6734.34J

Wab=0

In conclusion,

Wt=wac+Wc+Wba

Wt=4788.864J+0+(-6734.34J)

Wt=+1945.475J

Read more about work

brainly.com/question/756198

#SPJ1

8 0

2 years ago

A certain field line diagram illustrates the electric field due to three particles that carry charges 5.0 μC, -3.0 μC, and -2.0

4vir4ik [10]

Answer:

Explanation:

Number of lines emanate from + 5 micro coulomb is 15 .

They terminates at negative charges that means at - 3 micro coulomb and - 2 micro Coulomb.

the electric field lines terminates at - 3 micro Coulomb and - 2 micro Coulomb is in the ratio of 3 : 2.

So the lines terminating at - 3 micro coulomb

= $\frac{3}{5}\times 15 = 9$

So the lines terminating at - 2 micro coulomb

= $\frac{2}{5}\times 15 = 6$

So, the number of filed lines terminates at - 2 micro Coulomb are 6.

4 0

3 years ago

A force of 10N is applied by a boy while lifting a 20,000g mass. How much does it accelerate by?

Tanya [424]

Answer:

0.5 $m/s^{2}$

Explanation:

20000g to kg = $\frac{20000}{1000}$ = 20 kg

f = ma

a = $\frac{f}{m}$

a = $\frac{10}{20}$

a = $\frac{1}{2}$

a = 0.5 $m/s^{2}$

8 0

3 years ago