What carries electrons from the power supply to a load?

Some waves can only travel through matter. This matter is called _________.

yulyashka [42]

This matter is called medium

4 0

3 years ago

A 4 cm diameter "bobber" with a mass of 3 grams floats on a pond. A thin, light fishing line is tied to the bottom of the bobber

Tasya [4]

Answer:

Explanation:

Calculate the volume of the lead

$V=\frac{m}{d}\\\\=\frac{10g}{11.3g'cm^3}$

Now calculate the bouyant force acting on the lead

$F_L = Vpg$

$F_L=(\frac{10g}{11.3g/cm^3} )(1g/cm^3)(9.8m/s^2)\\\\=8.673\times 10^{-3}N$

This force will act in upward direction

Gravitational force on the lead due to its mass will act in downward direction

Hence the difference of this two force

$T=mg-F_L\\\\=(10\times10^{-3}kg(9.8m/s^2)-8.673\times 10^{-3}\\\\=8.933\times10^{-3}N$

If V is the volume submerged in the water then bouyant force on the bobber is

$F_B=V'pg$

Equate bouyant force with the tension and gravitational force

$F_B=T_mg\\\\V'pg=\frac{(8.933\times10^{-2}N)+mg}{pg} \\\\V'=\frac{(8.933\times10^{-2}N)+mg}{pg}$

Now Total volume of bobble is

$\frac{V'}{V^B} =\frac{\frac{(8.933\times10^{-2})+Mg}{pg} }{\frac{4}{3} \pi R^3 }\times100\\\\=\frac{\frac{(8.933\times10^{-2})+(3)(9.8)}{(1000)(9.8)} }{\frac{4}{3} \pi (4.0\times10^{-2})^3 }\times100\\\\$

= $\large\boxed{4.52 \%}$

7 0

3 years ago

Where do you find electromagnetic waves on earth? what are some everyday uses?

Norma-Jean [14]

Answer:

Radio waves are used for communications and radar. Microwaves are used to cook your food. Infrared waves are used in remote controls and are emitted from all warm objects, allowing them to be used to create heat-sensitive cameras.

Explanation:

Basically electromagnetic waves can be found in your everyday life.

8 0

3 years ago

Read 2 more answers

If we put negative charge between two similar positive charges then what is it's equilibrium? And how?

Gnesinka [82]

Your question has been heard loud and clear.

Well it depends on the magnitude of charges. Generally , when both positive charges have the same magnitude , their equilibrium point is towards the centre joining the two charges. But if magnitude of one positive charge is higher than the other , then the equilibrium point will be towards the charge having lesser magnitude.

Now , a negative charge is placed in between the two positive charges. So , if both positive charges have same magnitude , they both pull the negative charge towards each other with an equal force. Thus the equilibrium point will be where the negative charge is placed because , both forces are equal , and opposite , so they cancel out each other at the point where the negative charge is placed. However if they are of different magnitudes , then the equilibrium point will be shifted towards the positive charge having less magnitude.

Thank you

5 0

4 years ago

Read 2 more answers

During the course of a trajectory, is the vertical component of the velocity a constant or a changing value? ___________________

ICE Princess25 [194]

Answer:

1) Changing value

2) The velocity is decreasing for upward motion and increasing for downward motion due to gravitational force

Explanation:

1) A trajectory is the motion of an object which is being acted upon by specified forces. The flight path of an object in projectile motion is its trajectory

During the course of a trajectory, the vertical component of the velocity, $v_y$ , is a changing value

2) The vertical component of the velocity first decreases, during the upward motion, according to the following equation;

$v_y$ = $u_y$ - g·t

Where;

$v_y$ = The vertical component of the velocity after a given time, t

$u_y$ = The initial vertical velocity

t = The time of motion of the trajectory

g = The acceleration due to gravity ≈ 9.8 m/s²

When the vertical velocity of the object decreases to zero, which is the point at which the object reaches the maximum height of its motion, the direction of the vertical motion of the object reverses, and object begins to accelerate and increase its velocity downwards according to the following equation;

$v_y$ = $u_y$ + g·t

Therefore, the velocity of the object is decreasing on its way up, and then increasing on its way down.

3 0

3 years ago