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hoa [83]
3 years ago
11

Which atom has the weakest attraction for electrons in a chemical bond? A) a boron atom B) a calcium atom C) a fluorine atom D)

a nitrogen atom
Chemistry
1 answer:
Black_prince [1.1K]3 years ago
3 0
<span> The answer is
B) a calcium atom</span>
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If you add enzyme to a solution containing only the product(s) of a reaction, would you expect any substrate to form?
Masteriza [31]

Answer:

e

Explanation:

<em>Provided the reaction that leads to the formation of the products can proceed in both forward and backward directions, the correct answer would be yes because the reaction will proceed backward until equilibrium is reached.</em>

<u>For a reaction that can proceed both forward and backward, the addition of a catalyst increases the rate of reaction in both directions based on the fact that a catalyst cannot alter the equilibrium of a reaction. </u>

Hence, if an enzyme is added to the product of a reaction that has the potential to proceed in both forward and reverse reactions, a substrate would be expected to form because the reaction will proceed backward until an equilibrium is reached.

The correct option is e.

8 0
3 years ago
It would be nice if someone HELPED. During an experiment, you observe that two charged balloons repel each other. When you bring
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2 years ago
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Describe the similarities and differences between herbivores,carnivore,and omnivores​
vredina [299]

Answer:

Herbivores only eat plants . Remember HERBS are PLANTS.

Carnivores only eat meat. Remember CARNE = MEAT in Spanish.

Omnivores eat MEAT & PLANTS.

Explanation:

Differences are what they eat, similarities omnivores eat both.

3 0
3 years ago
8. If the temperature of a piece of steel decreases, what happens to its density?
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3 0
3 years ago
Determine the mass of CaCO3 required to produce 40.0 mL CO2 at STP. Hint use molar volume of an ideal gas (22.4 L)
cupoosta [38]

Answer:

m_{CaCO_3}=0.179gCaCO_3

Explanation:

Hello,

In this case, since the undergoing chemical reaction is:

CaCO_3(s)\rightarrow CaO(s)+CO_2(g)

The corresponding moles of carbon dioxide occupying 40.0 mL (0.0400 L) are computed by using the ideal gas equation at 273.15 K and 1.00 atm (STP) as follows:

PV=nRT\\\\n=\frac{PV}{RT}=\frac{1.00 atm*0.0400L}{0.082\frac{atm*L}{mol*K}*273.15 K})=1.79x10^{-3} mol CO_2

Then, since the mole ratio between carbon dioxide and calcium carbonate is 1:1 and the molar mass of the reactant is 100 g/mol, the mass that yields such volume turns out:

m_{CaCO_3}=1.79x10^{-3}molCO_2*\frac{1molCaCO_3}{1molCO_2} *\frac{100g CaCO_3}{1molCaCO_3}\\ \\m_{CaCO_3}=0.179gCaCO_3

Regards.

3 0
3 years ago
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