If a train starts from rest and after 0.5 hours travels at a speed of 75 km/hr, what is its
1 answer:
Answer:
150 km/hr²
Explanation:
The data for the motion of the train includes;
The train starts from rest, therefore, the initial velocity of the train, u = 0 km/hr
The speed of the train after 0.5 hours, v = 75 km/hr
The change in time during the motion of the train, Δt = 0.5 hours
The acceleration, 'a', is the rate of change of velocity with time;
Therefore, we have;
a = (75 km/hr - 0 km/hr)/(0.5 hr) = 150 km/hr²
a = 150 km/hr² = 150 km/hr² × 1,000 m/km × hr²/(3,600 s)² = 5/432 m/s²
The acceleration of the train, a = 150 km/hr² = 5/432 m/s².
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Answer:
Second option 6.3 N at 162° counterclockwise from
F1->
Explanation:
Observe the attached image. We must calculate the sum of all the forces in the direction x and in the direction y and equal the sum of the forces to 0.
For the address x we have:
For the address and we have:
The forces and
are known
We have 2 unknowns ( and b) and we have 2 equations.
Now we clear from the second equation and introduce it into the first equation.
Then
Then we find the value of
Finally the answer is 6.3 N at 162° counterclockwise from
F1->
