This problem is providing us with the percent composition of a compound containing magnesium, nitrogen, oxygen and water. Thus, the empirical formula is required and found to be Mg(NO₃)₂·6H₂O.
<h3>Empirical formulas</h3>
In chemistry, empirical formulas are used in order to figure out the minimum whole-number representation of a molecular formula, which contains the actual number of atoms.
Thus, we start determining it by assuming the given percentages as masses and calculating the moles with the atomic or molar mass of the involved species:
Next, we divide by the 0.386 as the smallest number of moles in order to determine their subscripts in the chemical formula:
Hence, the empirical formula turns out to be Mg(NO₃)₂·6H₂O, which is actually a hydrate (hexahydrate).
Learn more about percent composition: brainly.com/question/12247957
<span>The ratio of oxygen-16 and oxygen-18 isotopes in plankton fossils in deep-sea sediments can be used to determine past temperatures.</span>
Answer:
You know that nitrogen-14 has 7 protons in the nucleus because it is an isotope of nitrogen, which has an atomic number equal to 7 . Because nitrogen-14 is a neutral atom, the number of protons it has in its nucleus must be equal to the number of electrons that surround its nucleus.
Answer:
Are basic:
[OH⁻] = 3.13x10⁻⁷M and [H₃O⁺] = 9.55x10⁻⁹M
Explanation:
A solution is basic when pH = - log [H₃O⁺] is higher than 7.
It is possible to convert [OH⁻] to [H₃O⁺] using:
[H₃O⁺] = 1x10⁻¹⁴ / [OH⁻]
a. [OH⁻] = 3.13x10⁻⁷M
[H₃O⁺] = 1x10⁻¹⁴ / [3.13x10⁻⁷M]
[H₃O⁺] = 3.19x10⁻⁸M
pH = - log [H₃O⁺] = 7.50
[OH⁻] = 3.13x10⁻⁷M is basic
b. pH = -log [H₃O⁺] = - log 0.000747M = 3.13.
This solution is not basic
c. [H₃O⁺] = 9.55x10⁻⁹M
pH = 8.02
This solution is also basic.
Answer:
The answer is
<h2>150 mL</h2>
Explanation:
To convert the volume from cm³ to mL we use the conversion
1 cm³ = 1 mL
So from the question
if 1 cm³ = 1 mL
Then 150 cm³ = 150 mL
Hope this helps you