The free energy change of the reaction; Fe (s) + Au3+ (aq) -> Fe3+ (aq) + Au (s) is calculated to be -443.83KJ/mol.
For the reaction shown in question 7, we can divide it into half equations as follows;
Oxidation half equation;
6 Al (s) -------> 6Al^3+(aq) + 18e
Reduction half equation;
3Cr2O7^2-(aq) + 42H^+(aq) + 18e -----> 6Cr^3+(aq) + 21H2O(l)
The balanced reaction equation is;
6Al(s) + 3Cr2O7^2-(aq) + 42H^+(aq) -----> 6Al^3+(aq) + 6Cr^3+(aq) + 21H2O(l)
The E° of this reaction is obtained from;
E° anode = -0.04 V
E°cathode = +1.50 V
E° cell = +1.50 V - (-0.04 V) = 1.54 V
Given that;
ΔG° = -nFE°cell
n = 3, F = 96500, E°cell = 1.54 V
ΔG° = -(3 × 96500 × 1.54)
ΔG° = -443.83KJ/mol
Learn more: brainly.com/question/967776
The first diagram is showing carboxylic acid because carboxyl contains a Carbon atom as the central atom bonded with OH group, a double bonded Oxygen, hydrogen ofc, and a lone R group.
2. It is ester group
3. Correct its ether
4. It's the exact diagram for ethyl alcohol, so correct
WOOT WOOOT
Actually its the second and fourth one for sure! If you just put one it only gives parcel credit. ;-;
The combined gas<span> law states that the </span>pressure of a gas<span> is inversely related to the</span>volume<span> and directly related to the </span>temperature<span>. If </span>temperature<span> is held constant, the equation is </span>reduced<span> to Boyle's law. Therefore, if you </span>decrease<span> the </span>pressure<span> of a fixed amount of </span>gas<span>, its </span>volume<span> will increase.</span>
