During the period that the moon’s phases are changing from new to full, the moon is _____. waxing exhibiting retrograde motion w
2 answers:
You might be interested in
Answer:
on ear that is closer to Black hole.
On ear that is farther from Black hole.
Explanation:
This problem can be solved as two masses that are at two different location from a bigger mass whose gravity affects both.
tension is an equal and opposite force that is exerted in response to applied force.
so on ear that is closer to black hole would have tension that is equal in magnitude and opposite in direction to gravitational force that ear experience due to the black hole at that location.
this true for ear that is further away from black hole as well.
(1) Force on ear that is closer to black hole.
is mass of Black hole.
is mass of ear that is close to black hole.
r =
Note, we have subtracted because ear is closer to black hole.
plugging all this in formula gives.
That is tension of ear.
(2) Force on ear that is further from black hole.
is mass of Black hole.
is mass of ear that is close to black hole.
this time r is further away from black hole so it would be.
Plugging this all in we get
and that is tension on ear that is further from black hole.
Notice the tension difference, and order of magnitude of tension,it is enormous .
this astronaut is lethally close to black hole.
Answer:
The magnifying power of this telescope is (-60).
Explanation:
Given that,
The focal length of the objective lens of an astronomical telescope,
The focal length of the eyepiece lens of an astronomical telescope,
To find,
The magnifying power of this telescope.
Solution,
The ratio of focal length of the objective lens to the focal length of the eyepiece lens is called magnifying of the lens. It is given by :
m = -60
So, the magnifying power of this telescope is 60. Therefore, this is the required solution.