Answer:
The solid ball and hollow ball both will reach the bottom with the same speed.
Explanation:
The speed of the solid and hollow balls is independent of the mass and the radius. A solid and hollow ball experience same speed on a given incline.
The speed can be calculated as
v = √(10/7)gh
where g is gravitational acceleration and h is the height
sinθ = h/L
h = L*sinθ
h = 3*sin(35)
h = 1.72 m
v = √(10/7)*9.8*1.72
v = 4.91 m/s
Both balls will reach the bottom at the speed of 4.91 m/s.
This is the Doppler effect.
1. As the sound leaves the horn the sound waves are at first close to each other and as they move outwards they become further apart. The closer the sound waves are the louder the noise.
As the car gets the closer the sound waves get closer, so the horn becomes louder.
2. As the horn moves away, the sound waves become less frequent, causing the pitch to get lower.
Answer:
Here are the names and symbols
H is Hydrogen
Au is Gold
Potassium is K
Mg is Magnesium
Zinc is Zn
Iron is Fe
Cl is Chlorine
Na is Natrium/Sodium
Copper is Cu
Ag is Silver
<span>a)
Capacitance = k x ε° x area / separation
ε° = 8.854 10^-12 F/ m
k = 2.4max
average k = 0.78 / 1.27 * 2.4 +(1.27- 0.78) / 1.27 * 1 = 1.474 + 0.386 = 1.86
(61.4 % separation k = 2.4 --- 38.6 % k = 1 air --- average k = 0.614 * 2.34 + 0.386 * 1 = 1.86
area = 145 cm2 = 0.0145 m2
separation = 1.27 cm 0.0127 m
C = 1.86 * 8.854 10^-12 * 0.0145 / 0.0127 = 18.8 pF
b) Q = C * V --- 18.8 * 83 = 1560.4 pC = 1.5604 nC
c) E = V / d = 83 / 0.0127 = 6535.4 V/m </span>
To solve this problem we will apply the concepts related to Orbital Speed as a function of the universal gravitational constant, the mass of the planet and the orbital distance of the satellite. From finding the velocity it will be possible to calculate the period of the body and finally the gravitational force acting on the satellite.
PART A)
Here,
M = Mass of Earth
R = Distance from center to the satellite
Replacing with our values we have,
PART B) The period of satellite is given as,
PART C) The gravitational force on the satellite is given by,
