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SVEN [57.7K]
4 years ago
9

A parallel plate capacitor stores charge, and thus, stores energy in the form of electric potential energy. The total energy sto

red in a parallel plate capacitor does NOT depend on ________.
Physics
1 answer:
DIA [1.3K]4 years ago
7 0

Answer:

The charges on the plates,

Explanation:

A capacitor is an electronic device that can be used for storing of charges. A parallel plate capacitor consists of two plates of equal area separated by a dielectric constant. The energy stored in the capacitor is in the form of potential energy which comes into play during the discharging process of the capacitor.

The energy stored depends majorly on the voltage, area of the plates, distance between the plates and the nature of the dielectric constant of the material between the plates. But it does not depend on the charges on the plates.

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An infinitely long cylinder of radius R has linear charge density λ. The potential on the surface of the cylinder is V0, and the
tamaranim1 [39]

Answer:

V = V_0 - (lamda)/(2pi(epsilon_0))*ln(R/r)

Explanation:

Attached is the full solution

5 0
3 years ago
Which of the following best explains why you put
Ipatiy [6.2K]

Answer: to observe both solutions before the reaction

Explanation: just did it on edgen

6 0
4 years ago
A car traveling on a flat (unbanked), circular track accelerates uniformly from rest with a tangential acceleration of 1.85 m/s2
Tasya [4]

Answer:

Coefficient of friction = 0.836

Explanation:

If v be the speed after one quarter of the circular path

v² = 2as = 2 x 1.85 x 2πr/4 ; v²/r = 1.85 x 3.14 = 5.8

tangential acceleration = 5.8 m/s²

radial acceleration = v² /r = 5.8

total acceleration = √2 x 5.8

m x√2 x 5.8 = m x g xμ

μ = √2 x 5.8 / 9.8 = 0.836

7 0
3 years ago
A tuning fork of frequency 254 Hz and an open orang pipe of slightly lower frequency are at 15oC. When
katovenus [111]

The temperature of the air in the open orang pipe has been altered by 18.73° C

The frequency of an open orang pipe is estimated by using the formula:

\mathbf{f = \dfrac{v}{2L}}

Then, the combination of the frequency of the tuning fork and the open orang pipe is:

\mathbf{254 - \dfrac{v}{2L} }

These combinations of frequency produce 4 beats per sound.

i.e.

\mathbf{254 - \dfrac{v}{2L}   =4}

\mathbf{ \dfrac{v}{2L} = 254-4 }

\mathbf{ \dfrac{v}{2L} = 250 ----(1)}

When it is altered, the beats first diminish and increase again by 4.

i.e.

\mathbf{ \dfrac{v'}{2L} = 254+4 }

\mathbf{ \dfrac{v'}{2L} = 258 --- (2) }

If we equate both equations (1) and (2) together, we have:

\mathbf{\dfrac{v'}{v}= \dfrac{258}{250}}

However, from our previous knowledge, we understand that the velocity of an object varies directly proportional to the square root of its temperature.

Hence;

  • when the temperature of the pipe  = unknown ???
  • the temperature of the open orang pipe = 15

∴

\implies \mathbf{\sqrt{\Big(\dfrac{273 + T}{273 + 15}\Big)}= \dfrac{258}{250}}

By squaring both sides, we have:

\implies \mathbf{\Big(\dfrac{273 + T}{273 + 15}\Big)}= \Big (\dfrac{258}{250}\Big )^2}

\implies \mathbf{\Big(\dfrac{273 + T}{273 + 15}\Big)= \Big (\dfrac{66564}{62500}\Big )}

\implies \mathbf{\Big(\dfrac{273 + T}{288}\Big)= \Big (1.065024\Big )}

\implies \mathbf{273 +T =306.726912  }

T = 306.726912 - 273

T ≅ 33.73 ° C

∴

The change in temperature ΔT = 33.73° C - 15° C

The change in temperature ΔT = 18.73° C

Learn more about wave frequency here:

brainly.com/question/14316711?referrer=searchResults

4 0
3 years ago
5. A 500 kg satellite is in a circular orbit at an altitude of 500 km above the Earth's surface. Because of air friction, the sa
nika2105 [10]

Answer:

the energy transformed into internal energy is E fr = 1.57*10¹⁰ J

Explanation:

From energy conservation , the internal energy gained by friction should be equal to the loss of total energy of the satellite

Since the total energy of the satellite can be decomposed into kinetic and potential energy

E fr = ΔE = E₂-E₁

E₁=  K₁+V₁ = 1/2*m*v₁² + m*g*h₁

E₂ = K₂+V₂=  1/2*m*v₂² + m*g*h₂

first, we can choose our reference state so that h₂=0 and h₁=h=500 km

second , we can calculate the approximate the inicial velocity as the velocity required for a stable circular orbit

g = v₁²/(h+R) → v₁² = g*(h+R)

as the velocity diminishes, h diminishes, falling into the earth

assuming the radius of the Earth as R= 6371 km , then

v₁² = g*(h+R) = 9.8 m/s² * (500 km+ 6371 km) *1000 m/km = 6.73 * 10⁷ (m/s)²

replacing values

E₁ = 1/2*m*v₁² + m*g*h₁ = 1/2* 500kg *6.73 * 10⁷ (m/s)² + 500kg* 9.8m/s² * 500 km = 1.67*10¹⁰ J

E₂= 1/2*m*v₂² + m*g*h₂ =  1/2* 500kg *(2000 m/s)² + 0 = 1*10⁹ J

therefore

E fr = ΔE = E₂-E₁ = 1.67*10¹⁰ J - 1*10⁹ J = 1.57*10¹⁰ J  

5 0
3 years ago
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