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Tems11 [23]
3 years ago
6

¿por qué vías o medios llegan las enfermedades a nuestro organismo?​

Physics
1 answer:
Law Incorporation [45]3 years ago
8 0

Answer:

Las enfermedades infecciosas son causadas por gérmenes. Hay muchas formas diferentes de contraer una enfermedad infecciosa: A través del contacto directo con una persona que está enferma. Esto incluye besarse, tocarse, estornudar, toser y tener contacto sexual.

Explanation:

:)

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When a high-energy proton or pion traveling near the speed of light collides with a nucleus, it may travel 2.5 x 10-15 m before
Tasya [4]

Explanation:

It is given that,

When a high-energy proton or pion traveling near the speed of light collides with a nucleus, d=2.5\times 10^{-15}\ m

Speed of light, c=3\times 10^{8}\ m\s

Let t is the time interval required for the strong interaction to occur. The speed is given by :

c=\dfrac{d}{t}

t=\dfrac{d}{c}

t=\dfrac{2.5\times 10^{-15}\ m}{3\times 10^{8}\ m/s}

t=8.33\times 10^{-24}\ s

So, the time interval required for the strong interaction to occur is 8.33\times 10^{-24}\ s. Hence, this is the required solution.

8 0
3 years ago
What is the work of a 520n student walking a distance of 3 m
Wewaii [24]

Answer:

W=1560 Joules

Explanation:

Use W=fd

so, W=520N(3m)= 1560J

8 0
3 years ago
A 6 kg bowling ball is accelerated at a rate of 2.3 m/s² down the lane. How much force was necessary to produce this acceleratio
Maurinko [17]
The answer is D hoped this helped
4 0
3 years ago
In the early part of the 1900s, psychologists who broke down thought processes into their basic elements and analyzed them were
Svetlanka [38]

Answer: Cognitive

Explanation:

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8 0
3 years ago
A policeman in a stationary car measures the speed of approaching cars by means of an ultrasonic device that emits a sound with
beks73 [17]

Answer:

4.6 kHz

Explanation:

The formula for the Doppler effect allows us to find the frequency of the reflected wave:

f'=(\frac{v}{v-v_s})f

where

f is the original frequency of the sound

v is the speed of sound

vs is the speed of the wave source

In this problem, we have

f = 41.2 kHz

v = 330 m/s

vs = 33.0 m/s

Therefore, if we substitute in the equation we find the frequency of the reflected wave:

f'=(\frac{330 m/s}{330 m/s-33.0 m/s})(41.2 kHz)=45.8 kHz

And the frequency of the beats is equal to the difference between the frequency of the reflected wave and the original frequency:

f_B = |f'-f|=|45.8 kHz-41.2 kHz|=4.6 kHz

6 0
3 years ago
Read 2 more answers
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