Change in temperature = final temperature - Initial temperature
Δt = t₂ - t₁
Δt = 17 - (-6)
Δt = 17 + 6 = 23 f
In short, Your Answer would be Option D
Hope this helps!
Fusion and gravity is ur answer
Answer:
Power dissipated in resistor 532 ohm is 0.503 watt
Explanation:
We have given in first case resistance 
Power dissipated in this resistance is 
Power dissipated in the resistor is equal to 
We have to find the power dissipated in the resistor is 1.30 watt
From the relation we can say that 


So power dissipated in resistor 532 ohm is 0.503 watt
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