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Readme [11.4K]
3 years ago
14

Two blocks with different temperatures had entropies of 10 J/K and 30 J/K before they were brought in contact. What can you say

about the entropy of the combined system after the two came in contact with each other?a.Ssystem > 40 J/Kb.Ssystem = 20 J/K c.Ssystem < 20 J/Kd.Ssystem > 20 J/Ke.Ssystem = 40 J/Kf.Ssystem < 40 J/K
Physics
1 answer:
True [87]3 years ago
6 0

Answer:

a. Ssystem  > 40 J/K

Explanation:

Given that

The entropy of first block = 10 J/K

The entropy of second block = 30 J/K

When two bodies come into contact with each other, the entropy of the combined system will increase and the entropy sum remains unchanged: According to the Second law of thermodynamics.The entropy of the system will be greater than 40  J/K.

Therefore the answer is a.

Ssystem  > 40 J/K

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2 years ago
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C. A could be ruby (speed of light = 170,000 km/s); B could be diamond (speed of light = 120,000 km/s).

Explanation:

Refraction is a phenomenon that occurs when a light rays crosses the boundary between two different mediums.

When this occurs, the light wave changes speed and also direction, according to Snell's law:

n_1 sin \theta_1 = n_2 sin \theta_2 (1)

where

n_1 is the index of refraction of the first medium

n_2 is the index of refraction of the second medium

\theta_1 is the angle of incidence (the angle between the incident ray and the normal to the boundary)

\theta_2 is the angle of refraction (the angle between the refracted ray and the normal to the boundary)

The index of refraction is the ratio between the speed of light in a vacuum (c) and the speed of light in the medium (v):

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Using this definition, we can rewrite eq.(1) as

\frac{\sin \theta_2}{\sin \theta_1} = \frac{v_2}{v_1}

Where v_2 is the speed of light in the 2nd medium and v_1 the speed of light in the 1st medium.

Now let's analyze the situation represented in the figure: we see that as the light ray enters the 2nd medium, it bends towards the normal, this means that the angle of refraction is smaller than the angle of incidence:

\theta_2 < \theta_1

This means that

\frac{\sin \theta_2}{\sin \theta_1}

And therefore,

\frac{v_2}{v_1}

So, the speed of light in the second medium is smaller than the speed of light in the first medium: this occurs only in option C), which is therefore the correct choice.

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Answer:

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Answer:

(B) perpendicular to and in the same direction as the transverse electric wave

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