alguien me puede ayudar en química por favor no trolls es de suma importancia
1 answer:
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Answer:
D. It is limited to situations that involve aqueous solutions or specific compounds.
Explanation:
An Arrhenius acid is a substance that increases the concentration of H3O or H+ when dissolved in water. An Arrhenius base is a substance that increases the concentration of OH- when dissolved in water. These definitions tell us that D is indeed limited to situations that involve aqueous solutions or specific compounds, as aqueous means something that's dissolved in water.
A is wrong because the Bronsted-Lowry interpretation has a wider range of applications. Bronsted-Lowry acids and bases don't even need to be aqueous, so it is not limited to just aqueous solutions. They include any substance that can donate or accept a H+.
B is wrong because A is wrong. A and B basically say the same thing, that the Arrhenius interpretation has a wider range of applications than the Bronsted-Lowry interpretation.
C is wrong because the definition of an Arrhenius base is any substance that increases the concentration of OH-, or hydroxide ions. C completely counters this statement.
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Answer:
The correct answer is 0.024 M
Explanation:
First we use an ICE table:
Br₂(g) + F₂(g) ⇔ 2 BrF(g)
I 0.111 M 0.111 M 0
C -x -x 2 x
E 0.111 -x 0.111-x 2x
Then, we replace the concentrations of reactants and products in the Kc expression as follows:
Kc=
Kc=
54.7=
We can take the square root of each side of the equation and we obtain:
7.395=
0.111(7.395) - 7.395x= 2x
0.82 - 7.395x= 2x
0.82= 2x + 7.395x
⇒ x= 0.087
From the x value we can obtain the concentrations in the equilibrium:
[F₂]= [Br₂]= 0.111 -x= 0.111 - 0.087= 0.024 M
[BrF]= 2x= 2 x (0.087)= 0.174 M
So, the concentration of fluorine (F₂) at equilibrium is 0.024 M.