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allochka39001 [22]
3 years ago
11

How many boron atoms are there in 5 molecules of BF3? Hint: The symbol for boron is B. Submit​

Physics
2 answers:
Thepotemich [5.8K]3 years ago
8 0

Answer:

5 atoms of Boron

Explanation:

Boron makes up approximately 15.944% of the mass and the rest of the 84.056% is Fluorine. There is 5 Atoms because Boron atomic mass is 10.811 in 1 molecule of BF3 and you wanted 5 Molecules.

Drupady [299]3 years ago
6 0

Answer:

5 atoms of boron

Explanation:

it's because there is no number written next to the symbol 'B' so it means there's one boron so if we multiply it by 5 since there are 5 molecules it will give us the answer '5'.

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Why are airbags, helmets, and other safety devices important? Physics
Ivenika [448]

Answer:to prevent serious damage when an accident occur

Explanation:to prevent serious damage when accident occur

4 0
3 years ago
While in europe, if you drive 125 km per day, how much money would you spend on gas in one week if gas costs 1.10 euros per lite
Ymorist [56]
First we need to write the data given in the problem.
Given Data
Distance per day = 125km
Gas cost =1.10 Eu per liter
Car mileage= 37.0 mil/gal
1 Eu= 1.26$
Find
1 week expenditure on Gas =?

Solution
Distance in one week = 125 kmx 7 = 875 km or 543.7 miles
Gas consumed in one week = 543.7/37 = 14.694 gal or 52.99 litre

Answer
Cost of Gas per week = 52.99 x 1.10 = 58.28 Eu or 73.44$

Regards
8 0
3 years ago
If you ride an elevator moving forward with a constant speed, is your apparent weight same,greater than or less than your weight
wlad13 [49]
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6 0
3 years ago
A stone is tied to a string and whirled at constant speed in a horizontal circle. The speed is then doubled without changing the
Tanya [424]

Answer:

Afterward the magnitude of the acceleration of the stone is four times as great

Explanation:

A stone tied to a string and whirled at a constant speed in a horizontal circle will have a centripetal acceleration given by

a = \frac{v^{2} }{r}

Where a is the centripetal acceleration

v is the speed

and r is the radius of the circle

Here, the radius of the circle is the length of the string.

Now, from the question

The speed is then doubled without changing the length of the string,

Let the new speed be v_{2}, that is

v_{2} = 2v

and without changing the length of the string means radius r is constant.

To determine the magnitude of the acceleration of the stone afterwards,

Let the new acceleration be a_{2}.

Then we can write that

a_{2} = \frac{v_{2}^{2}  }{r}

From

a = \frac{v^{2} }{r}

v = \sqrt{ar}

Recall that

v_{2} = 2v

∴ v_{2} = 2\sqrt{ar}

Now, we will put the value of v_{2} into

a_{2} = \frac{v_{2}^{2}  }{r}

Then,

a_{2} = \frac{(2\sqrt{ar}) ^{2}  }{r}

a_{2} = \frac{4ar }{r}

a_{2} = 4a

The new magnitude of the acceleration of the stone is four times the initial acceleration.

Hence,

Afterward the magnitude of the acceleration of the stone is four times as great

3 0
3 years ago
If the resistance through the fat is 3 times that through the muscle, how much of the total current goes through the fat in term
lapo4ka [179]

Answer:

it A i think

hope that helps if not i can change it

Explanation:

8 0
2 years ago
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