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alexandr1967 [171]
3 years ago
13

N

Chemistry
1 answer:
andrey2020 [161]3 years ago
8 0

Answer:

yes

Explanation:

the definition for time is correct, the definition for speed is incorrect

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Osmium is the most dense element we know of. A 22 g sample of Osmium has a volume of 100 cL. Calculate the density of Osmium in
kakasveta [241]

Answer:

a. V = 1000 mL

b. Denisty = 0.022 g/mL

Explanation:

a.

First we need to convert the volume of the Osmium into mL. For that purpose we are given the conversion unit as:

1 mL = 0.1 cL

Hence, the given volume of Osmium will be:

V = Volume of Osmium = 100 cL = (100 cL)(1 mL/0.1 cL) = 1000 mL

<u>V = 1000 mL</u>

b.

The density of Osmium is given by the following formula:

Density = mass/Volume

Denisty = 22 g/1000 mL

<u>Denisty = 0.022 g/mL</u>

5 0
3 years ago
Choose the correct name for each acid. Click here
Zigmanuir [339]

Answer:

1. Nitrous Acid

2. Hydroiodic Acid

3. Phosphoric Acid

Explanation:

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3 years ago
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3) How many micrograms are found in 9.12 x 10-5 L of Water?
Ann [662]

Answer:

86.2 or 431/5

Explanation:

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3 years ago
2. When two forces act on an object in opposite directions, you calculate the net
exis [7]

When two forces act on an object in opposite directions, the net  force can be calculated by subtracting the two forces.

<u>Explanation:</u>

  • The net/final force by subtracting the two given opposite forces as asked in the above question.

For example: If you keep a bottle on the table, the downward force subtracted from the upward force will be equal to the net force.

  • If the net force equals zero then the objects will be balanced, otherwise unbalanced.

For example: In the tug of war when two forces are of different units the force with the greater strength will have an advantage, like if the team on the right is stronger than that of left than the rope will move towards the right.

5 0
3 years ago
The specific heat capacity of liquid water is 4.18 J/g oC. Calculate the quantity of energy required to heat 1.50 g of water fro
natima [27]

Answer: The quantity of heat required is 358.644 J.

Explanation:

Given: Specific heat capacity = 4.18 J/g^{o}C

Mass = 1.50 g

T_{1} = 26.5^{o}C

T_{2} = 83.7^{o}C

Formula used to calculate heat energy is as follows.

q = m \times C \times (T_{2} - T_{1})

where,

q = heat energy

m = mass

C = specific heat capacity

T_{1} = initial temperature

T_{2} = final temperature

Substitute the values into above formula as follows.

q = m \times C \times (T_{2} - T_{1})\\= 1.50 \times 4.18 J/g^{o}C \times (83.7 - 26.5)^{o}C\\= 358.644 J

Thus, we can conclude that quantity of heat required is 358.644 J.

5 0
3 years ago
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