A result of chemical change is

Two particles of a gas collide. Why is this considered an elastic collision? (1 point)

dezoksy [38]

I don’t know really really I don’t know

7 0

2 years ago

Student one used bowling ball A in a bowling game against Student 2, who used bowling ball B. Use Newton’s Three Laws of Motion

Jlenok [28]

Answer:

Newton’s Three Laws of Motion has a great impact.

Explanation:

Newton’s Three Laws of Motion has a great impact on the bowling game for the 2 students. When the student one throw ball to the student 2, the ball decrease its speed due to the gravity and opposing air. If these forces are removed from the system the ball will continue its motion till another force is applied on it. When the force applied to the ball it produces acceleration in the direction to the applied force. If the ball touches the ground it bounce back with equal force which is a reaction of the ground.

8 0

3 years ago

Which of the following represents an upright image? A. -do B. +m C. -m D. +do

Tom [10]

Answer:

B. +m

Explanation:

The magnification of an image is defined as the ratio between the size of the image and of the object:

$m = \frac{y'}{y}$

where we have

y' = size of the image

y = size of the object

There are two possible situations:

- When m is positive, y' has same sign as y: this means that the image image is upright

- When m is negative, y' has opposite sign to y: this means that the image is upside down

Therefore, the correct option representing an upright image is

B. +m

5 0

2 years ago

The most precise measurement of the speed of light in vacuum is 299,792,458 m/s. Which of the following values would you use to

Luda [366]

Answer:

v = 3.00 x 10⁸ m/s

Explanation:

given,

speed of light in vacuum = 299,792,458 m/s

speed of light in scientific notation to three significant figures

v = 2.99792458 x 10⁸ m/s

by rounding off the speed to three significant figure.

v = 3.00 x 10⁸ m/s

On the fourth place the value is greater than 5 so, on the third place 1 will be added.

now, the speed with three significant figure comes out to be

v = 3.00 x 10⁸ m/s

3 0

2 years ago

ILI

Nikolay [14]

The original kinetic energy will be 0 J and the final kinetic energy will be 7500 J and the amount of work utilized will be similar to the final kinetic energy i.e., 7500 J.

Explanation:

As it is known that the kinetic energy is defined as the energy exhibited by the moving objects. So the kinetic energy is equal to the product of mass and square of the velocity attained by the car. Thus,

$\text {Kinetic energy}=\frac{1}{2} m v^{2}$

So the initial kinetic energy will be the energy exerted by the car at the initial state when the initial velocity is zero. Thus the initial kinetic energy will be zero.

The final kinetic energy is

$\text {Kinetic energy}=\frac{1}{2} m v^{2}=\frac{1}{2} \times 600 \times 5 \times 5$ = 7500 J

As the work done is the energy required to start the car from zero velocity to 5 m/s velocity.

Work done = Final Kinetic energy - Initial Kinetic energy

Thus the work utilized for moving the car is

Work done = 7500 J - 0 J = 7500 J

Thus, the initial kinetic energy of the car is zero, the final kinetic energy is 7500 J and the work utilized by the car is also 7500 J.

7 0

2 years ago