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ivanzaharov [21]
3 years ago
11

d. Butanol has the chemical formula C4H,OH. Write and balance the chemical reaction for the combustion of butanol.​

Chemistry
1 answer:
valentina_108 [34]3 years ago
7 0

Answer:

C4H9OH + 6O2 → 4CO2 + 5H2O

Explanation:

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When two moles of ethane react completely with oxygen, how many moles of carbon dioxide will be produced?A. 2.B. 4.C. 8.D. Unkno
babymother [125]

Answer:

Option B.

Explanation:

As any reaction of combustion, the O₂ is a reactant and the products are CO₂ and H₂O. Combustion reaction for ethane is:

2C₂H₆  +  7O₂   →   4CO₂  +  6H₂O

So 2 moles of ethane react with 7 moles of oxygen to make 4 moles of dioxide and 6 moles of water.

Then 2 moles of ethane will produce 4 moles of CO₂

6 0
3 years ago
Think about chemicals you may have in your home and list as many as you can think of:
MAVERICK [17]

Sucrose; C12H22O11

C9H8O4; acetyl salicylic acid

H2O2; hydrogen peroxide,

NaOH; sodium hydroxideExplanation:

6 0
3 years ago
Read 2 more answers
Why do airbags fill evenly with gases?
Firdavs [7]

Answer:

The signal from the deceleration sensor ignites the gas-generator mixture by an electrical impulse, creating the high-temperature condition necessary for NaN3 to decompose. The nitrogen gas that is generated then fills the airbag.

basically, the nitrogen fills the bag

8 0
2 years ago
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When a lead acid car battery is recharged by the alternator, it acts essentially as an electrolytic cell in which solid lead(II)
lesya692 [45]

Answer: The mass of lead deposited on the cathode of the battery is 1.523 g.

Explanation:

Given: Current = 62.0 A

Time = 23.0 sec

Formula used to calculate charge is as follows.

Q = I \times t

where,

Q = charge

I = current

t = time

Substitute the values into above formula as follows.

Q = I \times t\\= 62.0 A \times 23.0 sec\\= 1426 C

It is known that 1 mole of a substance tends to deposit a charge of 96500 C. Therefore, number of moles obtained by 1426 C of charge is as follows.

Moles = \frac{1426 C}{96500 C/mol}\\= 0.0147 mol

The oxidation state of Pb in PbSO_{4} is 2. So, moles deposited by Pb is as follows.

Moles of Pb = \frac{0.0147}{2}\\= 0.00735 mol

It is known that molar mass of lead (Pb) is 207.2 g/mol. Now, mass of lead is calculated as follows.

No. of moles = \frac{mass}{molar mass}\\ 0.00735 = \frac{mass}{207.2 g/mol}\\mass = 1.523 g

Thus, we can conclude that the mass of lead deposited on the cathode of the battery is 1.523 g.

3 0
2 years ago
Can you help me please, I’ll mark brainliest.
GrogVix [38]

Answer:

i think A

Explanation:

6 0
3 years ago
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