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2 years ago

How many grams of h2 will be produced from 12 grams of mg?.

Chemistry

1 answer:

GalinKa [24]2 years ago

4 0

Answer:

The molecular weight of Mg is 24.3 so 12 grams is 0.494 mole. So, since for every mole of Mg will result in one mole of H2, then, 0.494 mol of Mg will result in the formation of 0.494 mol of H2.

Explanation:

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What is the conjugate acid for the base, NH4?

Anastasy [175]

Answer:

NH4+ is the conjugate acid of the base NH3.

Explanation:

4 0

3 years ago

What is the mass in grams of 7.5 mol of C8H18?

Lana71 [14]

Answer:

$\boxed {\boxed {\sf 856.74 \ g \ C_8H _{18}}}$

Explanation:

To convert from grams to moles, the molar mass is used. These values tells us the grams in 1 mole of a substance. They can be found on the Periodic Table (they are equivalent to the atomic masses, but the units are grams per mole).

We are given the compound C₈H₁₈. Look up the molar masses of the individual elements.

Carbon (C): 12.011 g/mol
Hydrogen (H): 1.008 g/mol

Notice there are subscripts that tell us the number of atoms of each element. We must multiply the molar masses by the subscripts.

C₈: 8(12.011 g/mol)=96.088 g/mol
H₁₈: 18(1.008 g/mol)=18.144 g/mol

Add these 2 values together to find the molar mass of the whole compound.

C₈H₁₈: 96.088 g/mol +18.144 g/mol=114.232 g/mol

Use this number as a ratio.

$\frac{ 114.232 \ g \ C_8H_{18}}{1 \ mol \ C_8H_{18}}$

Multiply by the given number of moles: 7.5

$7.5 \ mol \ C_8H_{18}*\frac{ 114.232 \ g \ C_8H_{18}}{1 \ mol \ C_8H_{18}}$

The moles of C₈H₁₈ will cancel each other out.

$7.5 *\frac{ 114.232 \ g \ C_8H_{18}}{1}$

$7.5 *{ 114.232 \ g \ C_8H_{18}}$

$856.74 \ g \ C_8H _{18}$

7.5 moles of C₈H₁₈ is equal to <u>856.74 grams of C₈H₁₈</u>

8 0

3 years ago

Atoms of which two elements have a combined total of 23 protons?

Alik [6]

Answer:

Sodium, Na, and magnesium, Mg

6 0

4 years ago

If you have 30.O g of hydrogen gas burned in excess oxygen how many moles of water can you make

vladimir1956 [14]

Answer:

15 moles

Explanation:

Data given:

mass of hydrogen (H₂) = 30.0 g

amount of oxygen (O₂) = excess

moles of water = ?

Solution:

First we look to the reaction in which hydrogen react with oxygen and make (H₂O)

Reaction:

2H₂ + O₂ -----------> 2H₂O

Now look at the reaction for mole ratio

2H₂ + O₂ -----------> 2H₂O

2 mole 2 mole

So it is 2:2 mole ratio of hydrogen to water

As we Know

molar mass of H₂ = 2(1) = 2 g/mol

molar mass of H₂O = 2(1) + 16 = 18 g/mol

Now convert moles to gram

2H₂ + O₂ -----------> 2H₂O

2 mole (2 g/mol) 2 mole (18 g/mol)

4 g 36 g

So,

we come to know that 4 g of hydrogen gives 36 g of water then how many grams of water will be produce by 30 grams of hydrogen.

Apply unity formula

4 g of H₂ ≅ 36 g of H₂O

30 g of H₂ ≅ X of H₂O

Do cross multiplication

X of H₂O = 30 g x 36 g / 4 g

X of H₂O = 270 g

Now convert grams of H₂O into moles

No. of moles = mass in grams/molar mass

Put values in above formula

No. of moles = 270 g / 18 (g/mol)

No. of moles = 15 mol

so 30 gram of hydrogen produce 15 mol of water.

5 0

3 years ago

____ KClO3-----> ____ KCl + ____O3

djyliett [7]

Answer:

explain what need to be done here pls? what do you need?

Explanation:

6 0

3 years ago

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