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Kipish [7]
3 years ago
11

The sideview mirrors on cars are convex mirrors. Let's say the mirror on the driver's side of your car has a focal length with a

magnitude of 6.90 m and a truck is at a distance of 4.00 m from the mirror. The truck is the object for the convex sideview mirror. Determine the following:
a. Image distance of the truck (Include the appropriate positive or negative sign.)
b. Magnification for this object distance (Include the appropriate positive or negative sign.)
Physics
1 answer:
Arisa [49]3 years ago
6 0

Answer:

a)  i = -2.53 m , b)  m = 0.63

Explanation:

a) For this exercise we use the constructor equation

     1 / f = 1 / o + 1 / i

Where f is the focal length, o the distance to the object and i the distance to the image

In this exercise they give the focal length f = -6.90 m, the negative sign is a convex mirror, and the distance to the object is o = 4.00 m

 Let's find the distance to the image

         1 / i = 1 / f - 1 / o

         1 / i = 1 / -6.90 - 1/4

          1 / i = -0.1449-0.25 = 0.3949

          i = -2.53 m

.b) the expression for the magnification is

          m = - i / o

          m = - (-2.53) / 4

          m = 0.63

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A motorcycle is moving at a constant velocity of 15 meters/second. Then it starts to accelerate and reaches a velocity of 24 met
andrew11 [14]

Answer: 3 m/s^2

Explanation:

The acceleration of the motorcycle is given by

a=\frac{v-u}{t}

where

v=24 m/s is the final velocity of the motorcycle

u=15 m/s is the initial velocity

t=3 s is the time taken

Substituting these numbers into the equation, we find

a=\frac{24 m/s-15 m/s}{3 s}=\frac{9 m/s}{3s}=3 m/s^2

4 0
4 years ago
Read 2 more answers
A ray of light in glass strikes a water-glass interface at an angle of incidence equal to one-half the critical angle for that i
fomenos

Answer:

Explanation:

There will not be any internal reflection . it will be only refraction

critical angle = θ

Sinθ = 1 / μg

μg = 1.43 / 1.33 =

Sinθ = 1.33 / 1.43

= .93

θ = 68.44

angle of incidence i = 68.44 / 2

= 34.22

Sin i / Sin r = μw = 1.33 / 1.43  

= .93

sin 34.22  / sinθ₁ = .93 , θ₁ is angle of refraction.

sinθ₁ = sin 34.22 / .93

= .5623 / .93

= .6047

θ₁ = 37 degree Ans

5 0
3 years ago
A football player who weighs 550 N stands indoors wearing her football boots. The boot’s
EleoNora [17]

Answer:

183333 Pa

Explanation:

The weight of the football player is : 550 N ,thus the force the player exerts on the floor is 550 N

The area of blades in contact with the floor is = 30cm² = 0.003 m²

Pressure = Force / Area

Pressure = 550 / 0.003

Pressure = 183333 Pa

3 0
3 years ago
Two long parallel wires are separated by 6.0 mm. The current in one of the wires is twice the other current. If the magnitude of
lions [1.4K]

Answer:

Explanation:

Magnitude of force per unit length of wire on each of wires

= μ₀ x 2 i₁ x i₂ / 4π r    where i₁ and i₂ are current in the two wires , r is distance between the two and  μ₀ is permeability .

Putting the values ,

force per unit length = 10⁻⁷ x 2 x i x 2i / ( 6 x 10⁻³ )

= .67 i² x 10⁻⁴

force on 3 m length

= 3 x .67 x 10⁻⁴ i²

Given ,

8 x 10⁻⁶ = 3 x .67 x 10⁻⁴ i²

i²  = 3.98 x 10⁻²

i = 1.995 x 10⁻¹

= .1995

=  0.2 A approx .

2 i = .4 A Ans .

6 0
4 years ago
A motor has an armature resistance of 3.75 Ω . Part A If it draws 9.10 A when running at full speed and connected to a 120-V lin
bulgar [2K]

Back emf is 85.9 V.

<u>Explanation:</u>

Given-

Resistance, R = 3.75Ω

Current, I = 9.1 A

Supply Voltage, V = 120 V

Back emf = ?

Assumption - There is no effects of inductance.

A motor will have a back emf that opposes the supply voltage, as the motor speeds up the back emf increases and has the effect that the difference between the supply voltage and the back emf is what causes the current to flow through the armature resistance.

So if 9.1 A flows through the resistance of 3.75Ω then by Ohms law,

The voltage across the resistance would be

v = I x R

  = 9.1 x 3.75

  = 34.125 volts

We know,

supply voltage = back emf + voltage across the resistance

By plugging in the values,

120 V = back emf + 34.125 V

Back emf = 120 - 34.125

                = 85.9 Volts

Therefore, back emf is 85.9 V.

4 0
3 years ago
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