I think it's 10 but i may not be right so, sorry if it's wrong lol
Answer:
340 grams Ca₃P₂ (2 sig. figs.)
Explanation:
3Ca + 2P => Ca₃P₂
5.6 mole + excess => ? grams
Convert the 'known' to a coefficient of 1 by dividing all coefficients by 3.
=> Ca + 2/3P => 1/3Ca₃P₂
From the above, 1 mole of Ca => 1/3 mole Ca₃P₂
∴ 5.6 mole Ca in an excess of P => 1/3(5.6 mole) Ca₃P₂
=> 1.8666 mol Ca₃P₂ (calculator answer) ≅ 1.9 mol Ca₃P₂
=> 1.9 mole x 182 g Ca₃P₂/mol Ca₃P₂ = 339.73333 grams Ca₃P₂
≅ 340 grams Ca₃P₂ (2 sig. figs.)
A mole is a rather unusual unit of measurement. It is defined by a specific number of particles, molecules, atoms, or any other unit.
That number happens to be 6.022×10²³.
When we talk about a mole of water, then, we refer to 6.022×10²³ molecules of water.
Comparing 1 mole of 02 with 1 mole of CO:
This means means that both quantities will have the same number of molecules. The answer is C.
It may be tempting to select D, since it relates to the number of atoms rather than mass or volume, and moles are related to this idea. However, keep in mind that one mole of O2 will actually have twice as much oxygen atoms as one mole of CO, since there are two oxygen atoms per O2 molecule and only 1 oxygen atom per CO molecule.
Answer:
19.5g
Explanation:
Given parameters:
Volume of propane gas = 9.95L
Unknown:
Mass of propane gas = ?
Solution:
To solve this problem, find the number of moles first.
At STP;
22.4L of gas makes up 1 mole
9.95L of gas will have a 
= 0.44mole
So;
Mass of propane gas = number of moles x molar mass
Molar mass of propane = 3(12) + 8(1) = 44g/mol
Mass = 0.44 x 44 = 19.5g
Answer:
Na⁺ (aq) + OH⁺ (aq) + H⁺ (aq) + Cl⁻ (aq) → Na⁺ (aq) + Cl⁻ (aq) + H₂O (l)
General Formulas and Concepts:
<u>Atomic Structure</u>
<u>Aqueous Solutions</u>
- Solubility Rules
- States of matter
<u>Stoichiometry</u>
- Reaction RxN Prediction
- Balancing Reactions RxN
Explanation:
<u>Step 1: Define</u>
NaOH reacting w/ HCl
NaOH is soluble
HCl is soluble
[RxN] NaOH (aq) + HCl (aq) → NaCl (aq) + H₂O (l)
<u>Step 2: Total Ionic Equation</u>
<em>Break up soluble compounds into ionic form.</em>
[T.I.E] Na⁺ (aq) + OH⁺ (aq) + H⁺ (aq) + Cl⁻ (aq) → Na⁺ (aq) + Cl⁻ (aq) + H₂O (l)
