To solve this problem, we should recall that
the change in enthalpy is calculated by subtracting the total enthalpy of the reactants
from the total enthalpy of the products:
ΔH = Total H of products – Total H of reactants
You did not insert the table in this problem, therefore I
will find other sources to find for the enthalpies of each compound.
ΔHf CO2 (g) = -393.5 kJ/mol
ΔHf CO (g) = -110.5 kJ/mol
ΔHf Fe2O3 (s) = -822.1 kJ/mol
ΔHf Fe(s) = 0.0 kJ/mol
Since the given enthalpies are still in kJ/mol, we have to
multiply that with the number of moles in the formula. Therefore solving for ΔH:
ΔH = [<span>3 mol </span><span>( − </span><span>393.5 </span>kJ/mol<span>) + 1 mol (</span>0.0
kJ/mol)<span>] − [</span><span>3 mol </span><span>( − </span><span>110.5 </span>kJ/mol<span>) + </span><span>2 mol </span><span>( − </span><span>822.1 </span>kJ/mol<span>)]</span>
ΔH = <span>795.2
kJ</span>
Answer: 2.3 moles
Explanation:
Recall that based on Avogadro's law, 1 mole of any substance has 6.02 x 10^23 atoms
So if 1 mole of Aluminum = 6.02 x 10^23 atoms
Then, Z moles = 1.4 x 10^24 atoms
To get the value of Z, we cross multiply:
1 mole x 1.4 x 10^24 atoms = Z x (6.02 x 10^23 atoms)
1.4 x 10^24 atoms = Z x (6.02 x 10^23)
Hence, Z = (1.4 x 10^24 atoms) ➗ (6.02 x 10^23 atoms)
Z =2.3 moles
Thus, there are 2.3 moles in 1.4 x 10^24 atoms of aluminum.
I hope you understood
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