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mr Goodwill [35]
3 years ago
11

The maximum allowable resistance for an underwater cable is one hundredth of an ohm per

Physics
1 answer:
Studentka2010 [4]3 years ago
6 0

Answer:

A = 1.54 x 10⁻⁵ m² = 15.4 mm²

Explanation:

The resistance of a wire can be given by the following formula:

R = \frac{\rho L}{A}\\\\A = \frac{\rho L}{R} = \frac{\rho}{\frac{R}{L} }

where,

A = smallest cross-sectional area = ?

ρ = resistivity of copper = 1.54 x 10⁻⁸ Ωm

\frac{R}{L} = resistance per unit length of wire = 0.001 Ω/m

Therefore,

A = \frac{1.54\ x\ 10^{-8}\ \Omega m}{0.001\ \Omega/m}

<u>A = 1.54 x 10⁻⁵ m² = 15.4 mm²</u>

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