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The rounding up of the aforementioned number to four significant figures is as follows: 3.002 × 10²
<h3>What are significant figures?</h3>
Significant figures are figures that contribute to the general and overall value of the whole number.
Significant figures or digits are specifically meaningful with respect to the precision of a measurement.
Although, the original number given in this question has 9 significant figures, the number; 300.235800 can be rounded up to four significant figures as follows:
- Decimal notation: 300.2
- No. of significant figures: 4
- No. of decimals: 1
- Scientific notation: 3.002 × 10²
Therefore, the rounding up of the aforementioned number to four significant figures is as follows: 3.002 × 10².
Learn more about significant figures at: brainly.com/question/14359464
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This problem is providing the ratio of nitrogen to oxygen by mass in nitrogen monoxide, NO, as 7.0:8.0 and asks for the same ratio but in NO₂ and N₂O₇. After doing the calculations, the results are 7.0:16.0 and 1.0:4.0 respectively.
<h3>Mass ratios:</h3>
In chemistry, one can calculate the mass ratios in chemical formulas according to the atomic mass of each atom. In such a way, one knows the mass ratio of nitrogen to oxygen in NO is 7.0:8.0 because we divide the atomic mass of nitrogen by oxygens:
Now, for chemical formulas with subscripts, one must multiply the atomic mass of the element by the subscript in the formula, which is the case of NO₂ and N₂O₇ as shown below:
Therefore, the results for NO₂ and N₂O₇ are 7.0:16.0 and 1.0:4.0 respectively
Learn more about atomic masses: brainly.com/question/5566317
The second volume : V₂= 0.922 L
<h3>
Further explanation
</h3><h3>Given
</h3>
7.03 Liters at 31 C and 111 Torr
Required
The second volume
Solution
T₁ = 31 + 273 = 304 K
P₁ = 111 torr = 0,146 atm
V₁ = 7.03 L
At STP :
P₂ = 1 atm
T₂ = 273 K
Use combine gas law :
P₁V₁/T₁ = P₂V₂/T₂
Input the value :
0.146 x 7.03 / 304 = 1 x V₂/273
V₂= 0.922 L
Water is the answer out of all the other options
