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ohaa [14]
3 years ago
8

After turning on the power source connected to your two electrodes, we expect to see the microbeads moving through the solution.

What forces are acting on the microbeads as they move (ignore vertical forces)
Physics
1 answer:
Rudik [331]3 years ago
4 0

Answer:

the pearls have an electrical charge induced by contact with the ions of the solution and these charges are attracted by the electrode by a force electric

Explanation:

The pearls are suspended in a solution, when connecting the power source, it is subjected to an electric shock, the pearls have an electrical charge induced by contact with the ions of the solution and these charges are attracted by the electrode by a force electric

            F = q E

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A certain electric dipole consists of charges q and –q separated by distance d, oriented along the x-axis as shown in the figure
Anna71 [15]

Electric field due to a point charge is given by formula

E = \frac{kq}{r^2 + \frac{d^2}{4}}

now due to negative charge also the magnitude of electric field will be same

only difference is the direction of field due to negative charge is radially inwards

now we can say that net field due to these two charges is given as

E = 2E_0cos\theta

E = 2\frac{kq}{r^2 + \frac{d^2}{4}}*\frac{d/2}{\sqrt{r^2 + \frac{d^2}{4}}}

E = \frac{kqd}{(r^2 + \frac{d^2}{4})^1.5}

now it is given that distance r is very large than "d" so we can say

E = \frac{kqd}{r^3}

<em>so above is the electric field due to dipole</em>

7 0
3 years ago
A loop of wire is placed in a magnetic field such that it has a flux, LaTeX: \phi ϕ, through it. The loop is compressed so that
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Answer:

B'= 3.333 B

Explanation:

Lets take

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We know that flux ,Ф

Ф = B A

Given that flux is constant so

B A = B' A'

B A=B' x 0.3 A

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It means that magnetic field will increase.

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If i thought about this properly the answer is b
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