Question

Sulfur reacts with oxygen to form sulfur dioxide (SO2(g), mc010-1.jpgHf = –296.8 kJ/mol) according to the equation below. mc010-2.jpg What is the enthalpy change for the reaction?
–593.6 kJ –296.8 kJ 296.8 kJ 593.6 kJ

Answer 1

Answer:

b

Explanation:

Answer 2

We want: 
S(s) + O2(g) --> SO2(g) 
So the following are the given:
1) S(s) + 3/2O2(g) --> SO3(g) ∆H = -395.8 kJ/mole 
2) 2SO2 + O2 --> 2SO3(g) ∆H = -198.2 kJ/mole 
Reverse Equation 2) and then  divide by 2 
SO3(g) --> SO2(s) + 1/2O2(g) ∆H = +99.1 kJ/mole 
Add Equation 1) 
S(s) + O2(g) --> SO2(g) ∆H = -296.7 kJ/mole