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3 years ago

What would make bromine a group 17 element more similar to a noble gas

Chemistry

2 answers:

NeTakaya3 years ago

7 0

It is the chemiclas that is needed in the chimstry in science class

Dmitriy789 [7]3 years ago

6 0

Bromine has 7 electrons in it's outer shell, if it gains an extra electron it will have a full outer shell making it stable like a noble gas.

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Light travels at a speed of 3.00 × 1010 cm/sec. What is the speed of light in kilometers/hour?

snow_lady [41]

Answer:

300,000km is the speed of light

4 0

3 years ago

Which of the following is not an organic compound?<br> Corn oil<br> Bromine<br> Methane<br> Protein

zloy xaker [14]

The correct answer is Bromine
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6 0

3 years ago

Consider the reaction:

kramer

Answer:

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Explanation:

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3 0

3 years ago

A gas bubble has a volume of 0.650 mL at the bottom of a lake, where the pressure is

astraxan [27]

Considering the Boyle's law, as the pressure decreases, volume increases and has a value of 2.246 mL.

<h3>Boyle's law</h3>

Boyle's law establishes the relationship between the pressure and the volume of a gas when the temperature is constant.

This law says that the volume occupied by a given mass of gas at constant temperature is inversely proportional to the pressure. This means that if the pressure increases, the volume decreases, while if the pressure decreases, the volume increases.

Boyle's law is expressed mathematically as:

P×V=k

If an initial state 1 and a final state 2 are analyzed, Boyle's law is expressed as:

P1×V1=P2×V2

<h3>Volume at the surface of the lake</h3>

In this case, you know:

P1= 3.46 atm
V1= 0.650 mL
P2= 1 atm
V2= ?

Replacing in Boyle's law:

3.46 atm× 0.650 mL= 1 atm×V2

Solving:

V2= (3.46 atm× 0.650 mL)÷ 1 atm

Finally, as the pressure decreases, volume increases and has a value of 2.246 mL.

Learn more about Boyle's law:

brainly.com/question/4147359

#SPJ1

4 0

2 years ago

An empty container weighs 80.21 g. it is filled with 20.14 mL of an unknown liquid, and the total weight of the container and li

tatiyna

Answer:

1.242 g/mL

Explanation:

Step 1: Given data

Mass of the empty container (m₁): 80.21 g

Mass of the filled container (m₂): 105.22 g

Volume of the unknown liquid (V): 20.14 mL

Step 2: Calculate the mass of the liquid

The mass of the liquid is equal to the difference between the mass of the filled container and the mass of the empty container.

$m = m_2 - m_1 = 105.22g - 80.21 g = 25.01 g$

Step 3: Calculate the density of the unknown liquid

The density of the liquid is equal to its mass divided by its volume.

$\rho = \frac{m}{V} = \frac{25.01g}{20.14mL} = 1.242 g/mL$

4 0

3 years ago