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3 years ago

What are the 3 Newton's Laws

Physics

1 answer:

Citrus2011 [14]3 years ago

3 0

Explanation:

Newton's first law of motion

state If a body is at rest it remain at reast and if it is in a motion it continue it's motion unless a net external force acting on it.

This law also called law of inertia

Newton's second law motion

states that acceleration to the force acting on the body and inversely proportional to the mass of the body

Newton's third law motion It is not to exert a force abody without the body exerting a forces in the opposite direction

These forces are called action and reaction force.

hope it's helpful ❤❤

THANK YOU

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A 30.0-kgkg box is being pulled across a carpeted floor by a horizontal force of 230 NN , against a friction force of 210 NN . W

Agata [3.3K]

Answer:

The acceleration of the box is 0.67 m/s²

Explanation:

Given that,

Mass of box = 30.0 kg

Horizontal force = 230 N

Friction force = 210 N

We need to calculate the acceleration of the box

Using balance equation

$F-f_{k}=ma$

$a=\dfrac{F-f_{k}}{m}$

Where, F = horizontal force

$f_{k}$ =frictional force

m= mass of box

a = acceleration

Put the value into the formula

$a=\dfrac{230-210}{30}$

$a=0.67\ m/s^2$

Hence, The acceleration of the box is 0.67 m/s²

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3 years ago

The center of mass of a 0.30-kg (non-uniform) meter stick is located at its 45-cm mark. What is the magnitude of the torque (in

lbvjy [14]

Answer:

The magnitude of the torque due to gravity if it is supported at the 28-cm mark is 0.5 N-m.

Explanation:

Given that,

Mass of the meter stick, m = 0.3 kg

Center of mass is located at its 45 cm mark.

We need to find the magnitude of the torque due to gravity if it is supported at the 28-cm mark. Torque acting on the object is given by :

$\tau=r\times F\\\\\tau=(45-28)\times 10^{-2}\times 0.3\times 9.79\\\\\tau=0.499\ N-m$

$\tau=0.5\ N-m$

So, the magnitude of the torque due to gravity if it is supported at the 28-cm mark is 0.5 N-m.

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4 years ago

A car accelerates from 6.0 m/s to 18 m/s at a rate of 3.0 m/s2. How far does it travel while accelerating

AlekseyPX

Answer:

48m, hope this helps :)

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4 years ago

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3 years ago

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Murljashka [212]

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4 years ago