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2 years ago

Use the illustration to answer the question :)

Physics

1 answer:

Naily [24]2 years ago

4 0

Answer:

This type of heat transfer occurs inside materials, typically solid materials. The heat from the fire is passed from molecule to molecule along the length of the material. The fire will generally follow the heat or sometimes the heat from conduction may cause a new fire to ignite elsewhere. The conduction is happening in the walls of the fireplace

Explanation:

SKATE OR DIE> LOSER

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X = v xo t. x = (10.0 m/s)(3.53 s) x = ????

LenaWriter [7]

x = V<em>x</em> * t

given V<em>x</em> = 10m/s n t = 3.53s

x = 10 * 3.53

= 35.3m

7 0

3 years ago

Read 2 more answers

What happens in the crushing can experiment?

Dafna1 [17]

Explanation:

When hot water is poured on the can in a bucket of cold water, the can crushes off means it gets unshaped

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3 years ago

When you push a child on a swing, your action is most effective when your pushes are timed to coincide with the natural frequenc

OleMash [197]

Answer:

$T = 4.48 s$

we can see that this time period is independent of the mass of the child so answer would be same if the child mass is different

Explanation:

Natural frequency of a simple pendulum of L length is given as

$f = \frac{1}{2\pi}\sqrt{\frac{g}{L}}$

so the time period of the oscillation is given as

$T = 2\pi \sqrt{\frac{L}{g}}$

so we will have

$L = 5 m$

$T = 2\pi\sqrt{\frac{5}{9.81}}$

$T = 4.48 s$

also from above formula we can see that this time period is independent of the mass of the child so answer would be same if the child mass is different

3 0

3 years ago

Which factor below does NOT affect how fast a solute dissolves in a solvent?

vodomira [7]

There is no factor on your list of choices that has any effect.

7 0

3 years ago

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The mass of a radioactive substance follows a continuous exponential decay model, with a decay rate parameter of 1% per day. A s

Bumek [7]

Answer:

2,38kg

Explanation:

Mass in function of time can be found by the formula: $m_{(t)} =m_{0} e^{-kt}$ , where $m_{0}$ is the initial mass, t is the time and k is a constant.

Given that a sample decay 1% per day, that means that after first day you have 99% of mass.

$m_{(1)} =m_{0} e^{-k(1)}$ , but $m_{(1)}=\frac{99m_{0} }{100}$ , so we have $\frac{99m_{0} }{100}=m_{0}e^{-k}$ , then $k=-ln(\frac{99}{100})=0.01$

Now using k found we must to find $m_{(5)}$ .

$m_{(5)}=m_{0}e^{-(0.01)5}=2.5kge^{-0.05} =2.5x0.951=2.38kg$

6 0

3 years ago