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ANEK [815]
3 years ago
6

What is Alfunim second element ? Please help !!!

Chemistry
1 answer:
Vikentia [17]3 years ago
3 0
Aluminum? It is a chemical element with the symbol Al and atomic number 13. It is a silvery-white, soft, non-magnetic and ductile metal in the boron group. By mass, aluminium is the most abundant metal in the Earth's crust and the third most abundant element
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What is chemical change? what are some ways to tell chemical change happened?
andrew-mc [135]

Answer:

A chemical change occurs when the reactants chemical compositions have changed

Explanation:

a change in colour, change in temperature, change in smell, formation of a precipitate, or the formation of gas bubbles

Hopes this helps

4 0
2 years ago
Draw the major product formed when the structure shown below undergoes substitution in ch3ch2oh with heat. (use a wavy bond (sin
muminat

Answer:

Explanation:

The missing image is attached below.

The objective of this question is to draw the major product formed from the diagram attached below.

From the diagram attached, we will see the reaction of a tertiary alkyl halide together with a weak nucleophile (ch3ch2oh) undergoing a nucleophilic substitution (SN₁) mechanism to yield a racemic mixture(i.e., compound that is not optically active but contains an equal amount of dextrorotatory and levorotatory stereoisomers) as a product.

7 0
3 years ago
Coal is a fossil fuel which is used to produce electricity. Which of these statements best describes an outcome of coal mining o
Mumz [18]
It becomes rich in minerals
7 0
3 years ago
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Which of the following represent Dinitrogen tricarbide <br>1) NC <br>2) NC2 <br>3) N2C2 <br>4) N203​
Ganezh [65]
Hmmm i think 3) N2C2 is correct
7 0
3 years ago
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Calculate the pH for the following weak acid. A solution of HCOOH has 0.12M HCOOH at equilibrium. The Ka for HCOOH is 1.8×10−4.
Shtirlitz [24]

Answer:

the pH of HCOOH solution is 2.33

Explanation:

The ionization equation for the given acid is written as:

HCOOH\leftrightarrow H^++HCOO^-

Let's say the initial concentration of the acid is c and the change in concentration x.

Then, equilibrium concentration of acid = (c-x)

and the equilibrium concentration for each of the product would be x

Equilibrium expression for the above equation would be:

\Ka= \frac{[H^+][HCOO^-]}{[HCOOH]}

1.8*10^-^4=\frac{x^2}{c-x}

From given info, equilibrium concentration of the acid is 0.12

So, (c-x) = 0.12

hence,

1.8*10^-^4=\frac{x^2}{0.12}

Let's solve this for x. Multiply both sides by 0.12

2.16*10^-^5=x^2

taking square root to both sides:

x=0.00465

Now, we have got the concentration of [H^+] .

[H^+] = 0.00465 M

We know that, pH=-log[H^+]

pH = -log(0.00465)

pH = 2.33

Hence, the pH of HCOOH solution is 2.33.

7 0
3 years ago
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