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Ede4ka [16]
3 years ago
7

What is the correct answer?

Physics
1 answer:
sashaice [31]3 years ago
7 0

Answer:

D) 4

Explanation:

Roots of a polynomial must be factors of the last term.

In this case, the factors of 6 are +1, -1, +2, -2, +3, -3, +6, -6. The only factor that doesn't show up, given the options, is 4. This means that D is the correct answer.

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The relationship between the masses of the Earth, moon and sun and their distances to each other play critical roles in affecting tides

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Do the following calculation and express the final answer in
sammy [17]

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Explanation:

I got the same thing. So, i don't know but good luck

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The velocity as a function of time of a moving particle is given by v = α+ βt2 , where α and β are constants and t is time in s.
marin [14]

The acceleration of the particle at 3s is [tex]a = 6 \beta [/tex]

v  =  \alpha  +  \beta {t}^{2}

<h3>How to calculate acceleration </h3>

a =  \frac{dv}{dt} \\ v =  \alpha  +  \beta  {t}^{2} \\ \frac{dv}{dt}  = 0 + 2 \beta t \\

if Time is given as 3s

therefore, Acceleration is

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Acceleration is

a = 6 \beta

Read more about velocity:

brainly.com/question/19365526

6 0
2 years ago
A plane travels 395,000 meters in 9,000 seconds. What was its speed?
sladkih [1.3K]

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8 0
3 years ago
A spherical shell has inner radius Rin and outer radius Rout. The shell contains total charge Q, uniformly distributed. The inte
Tju [1.3M]

Answer:

  E = Q / 4 π ε₀  (r-R_int) / (R_put³ -R_int³)

Explanation:

For this exercise we can use Gauss's law

          Ф = ∫ E. dA = q_{int} / ε₀

Where q is the charge inside the surface.

In this case the surface must be a sphere, the electric field lines and the radius of the sphere are parallel, so the scalar product is reduced to the algebraic product

           ∫ E dA = q_{int}/ ε₀

The area of ​​a sphere is

           A = 4π r²

- The electric field for a distance r < R_int

The charge inside is zero, so the electric field

          E = 0        r <R_in t

- The field for a radio inside the shell

   Let's use the concept of density

         ρ = Q / V

         q = ρ (4/3 π r³)

         dq = ρ 4π r² dr

We substitute in the Gaussian equation

     E ∫ dA = ρ 4π r² dr / ε₀

    E 4π r² = ρ 4π/ε₀   r³ / 3

     E = ρ / 3ε₀ r

We evaluate between the lower limit r = R_int, E = 0 and the upper limit r = r, E = E

      E- 0 = ρ / 3ε₀ (r –R_int)

Density  is

      ρ = q / 4/3 π (R_out³ - R_int³)

Where R <r

     E = Q / 4 π ε₀  (r-R_int) / (R_put³ -R_int³)

5 0
3 years ago
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