Answer:
Force A=-−2,697.75 N
Force B=13, 488.75 N
Explanation:
Taking moments at point A, the sum of clockwise and anticlockwise moments equal to zero.
25 mg-20Fb=0
25*1100g=20Fb
Fb=25*1100g/20=1375g
Taking g as 9.81 then Fb=1375*9.81=13,488.75 N
The sum of upward and downward forces are same hence Fa=1100g-1375g=-275g
-275*9.81=−2,697.75. Therefore, force A pulls downwards
Note that the centre of gravity is taken to be half the whole length hence half of 50 is 25 m because center of gravity is always at the middle
Answer:
u = - 38.85 m/s^-1
Explanation:
given data:
acceleration = 2.10*10^4 m/s^2
time = 1.85*10^{-3} s
final velocity = 0 m/s
from equation of motion we have following relation
v = u +at
0 = u + 2.10*10^4 *1.85*10^{-3}
0 = u + (21 *1.85)
0 = u + 38.85
u = - 38.85 m/s^-1
negative sign indicate that the ball bounce in opposite directon
Answer:
c = 1163.34 J/kg.°C
Explanation:
Specific heat capacity:
"Specific heat capacity is the amount of heat energy required to raise the temperature of a substance per unit of mass. The specific heat capacity of a material is a physical property."
Use this equation:
mcΔT = ( mw c + mAl cAl ) ΔT'
Rearranging the equation to find the specific heat (c) you get this:
c = (( mw c + mAl cAl ) ΔT') / (mΔT)
c = (( 0.285 (4186) + (0.15)(900)) (32 -25.1)) / ((0.125) (95 - 32))
c = 1163.34 J/kg.°C
Answer:
OA. . review all safety procedures and the lab activity procedure
Explanation:
peer-to-peer networks
Explanation:
Networks designed to connects similar computers that shares data and software with each other are called peer-to-peer networks.
These networks are closely around and do not rely on information passing through a central data point.
- In a peer to peer connection, the computers have direct access to one another.
- The computers over the network becomes both client and server.
learn more:
Machines on public network brainly.com/question/10338479
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