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Tanzania [10]
2 years ago
6

show the trajectory of a body projected with an initial velocity vat an angle of departure thita is a paraboler​

Physics
1 answer:
Jobisdone [24]2 years ago
5 0

Answer:

Let me look up a couple of things regarding this question.

Explanation:

Then I will get back to you.

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A van is traveling on a road at a speed of 55 km/h. A girl sitting near the driver of the van throws a paper airplane to a boy a
aivan3 [116]
<span>A van is traveling on a road at a speed of 55 km/h relative to a
stationary observer on the side of the road. A girl sitting near the
driver of the van throws a paper airplane to a boy at the back of the
van with a speed of 2 km/h relative to the girl, the boy, and the van.

The speed of the paper airplane, relative to the same stationary observer
on the side of the road, is (55 - 2) = 53 km/h.  No rounding is necessary.</span>
5 0
3 years ago
Read 2 more answers
A white dwarf is not continuing in nuclear fusion, yet it still shines brightly for thousands of years because...
Afina-wow [57]

Explanation:

Understanding that stars are naturally quite hot, imagine I pulled a piece of hot iron from a furnace. It would glow a bright red, and then slowly fade to black as the iron cools.

White dwarfs glow for the same reason - they are HOT!

3 0
3 years ago
If a force of 12 N is applied to an object
Varvara68 [4.7K]

Answer:

<h3>The answer is 3 kg</h3>

Explanation:

The mass of the object can be found by using the formula

m =  \frac{f}{a}  \\

f is the force

a is the acceleration

From the question we have

m =  \frac{12}{4}  \\

We have the final answer as

<h3>3 kg</h3>

Hope this helps you

6 0
3 years ago
Four traveling waves are described by the following equations, where all quantities are measured in SI units and y represents th
agasfer [191]

Answer:

T_1=T_3=\dfrac{2\pi}{21}

T_2=T_4=\dfrac{2\pi}{42}

Explanation:

Wave 1, y_1=0.12\ cos(3x-21t)

Wave 2, y_2=0.15\ sin(6x+42t)

Wave 3, y_3=0.13\ cos(6x+21t)

Wave 4, y_4=-0.27\ sin(3x-42t)

The general equation of travelling wave is given by :

y=A\ cos(kx\pm \omega t)

The value of \omega will remain the same if we take phase difference into account.

For first wave,

\omega_1=21

\dfrac{2\pi }{T_1}=21

T_1=\dfrac{2\pi}{21}

For second wave,

\omega_2=42

\dfrac{2\pi }{T_2}=42

T_2=\dfrac{2\pi}{42}

For the third wave,

\omega_3=21

\dfrac{2\pi }{T_3}=21

T_3=\dfrac{2\pi}{21}

For the fourth wave,

\omega_4=42

\dfrac{2\pi }{T_4}=42

T_4=\dfrac{2\pi}{42}

It is clear from above calculations that waves 1 and 3 have same time period. Also, wave 2 and 4 have same time period. Hence, this is the required solution.

3 0
3 years ago
The diagram does not represent a real electric field because the field lines__<br> NEED ANSWERS NOW
prohojiy [21]

Answer:

cross at many points

Explanation:

According to the diagram it does not shows the real electric field as the electric field does not intersect with each other but according to the given diagram many lines are intersected with each other

So the correct option is C as it would be crossed at many points

Hence, the same would be relevant

6 0
3 years ago
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