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HACTEHA [7]
3 years ago
9

You need to build a prototype with machined parts that withstand a saline corrosive environment and temperatures above 200 degre

es F. Which materials can you use? (You can choose more than one chioce.) 1. Stainless steel 2. Mild steel 3. Polycaprolactone 4. Aluminum
Physics
1 answer:
kondor19780726 [428]3 years ago
5 0

Answer:

Stainless steel

Explanation:

I will try to order the solutions from the least correct to the most correct.

Since a temperature greater than 200 ° F is required, that is to say approximately 93 ° c, <em>Polycaprolactone</em> is the least indicated. Its melting point is approximately 60 ° C, so it would not serve the required application.

On the other hand we have<em> Untreated aluminum</em>, which although it has a melting point higher than the required one, without a zinc and magnesium treatment it will easily oxidize in a salty environment, so it cannot be used in this choice either.

We have to compare the two steels.

The<em> Mild Steel </em>has a better corrosion resistance than the previous ones, but in a long-term cycle it will end up full of corrosion and therefore its properties will be highly affected.

Finally, we have <em>stainless steel</em>, which, as the name implies, contains in some of its variations chromium, zinc or magnesium in its alloys, which makes it highly resistant to corrosion.

In addition its melting point is above 1500 ° c.

The best choice is stainless steel.

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7 0
1 year ago
Bill drives west at 20\, \dfrac{\text m}{\text s}20 s m ​ 20, start fraction, start text, m, end text, divided by, start text, s
vovangra [49]

Answer:

Positive Horizontal line, constant

Explanation:

4 0
2 years ago
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What energy is the candle giving off
gregori [183]
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5 0
3 years ago
Consider the uniform electric field E = (8.0ĵ + 2.0 ) ✕ 103 N/C. What is its electric flux (in N · m2/C) through a circular area
cluponka [151]

Answer:

5.09 x 10⁵ Nm²/C

Explanation:

The electric flux φ through a planar area is defined as the electric field Ε times the component of the area Α perpendicular to the field. i.e

φ = E A

From the question;

E = (8.0j + 2.0k) ✕ 10³ N/C

r = radius of the circular area = 9.0m

A = area of a circle = π r²           [Take π = 3.142]

A = 3.142 x 9² = 254.502m²

Now, since the area lies in the x-y plane, only the z-component of the electric field is responsible for the electric flux through the circular area.

Therefore;

φ = (2.0) x 10³ x 254.502

φ = 5.09 x 10⁵ Nm²/C

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4 0
2 years ago
Coherent monochromatic light of wavelength l passes through a narrow slit of width a, and a diffraction pattern is observed on a
geniusboy [140]

Answer:

λ = a

Explanation:

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         sin θ  = m λ/ a

the first zero of the diffraction occurs for m = 1

        sin θ  = λ / a

 

angles are generally very small and are measured in radians

         sin θ  = θ  = y / x

we substitute

         \frac{y}{x}  = \frac{\lambda}{a}

the width of the central maximum is twice the distance to zero

         w = 2y

in the exercise indicate that this width is equal to twice the distance to the screen (2x)

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we substitute

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          λ = a

we see that the width of the slit is equal to the wavelength used.

3 0
3 years ago
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