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ololo11 [35]
3 years ago
14

Draw the dot structure of CX4

Chemistry
1 answer:
hichkok12 [17]3 years ago
7 0

Refer to the attachment

You might be interested in
How many grams of PH3 will be produced if 6.0 l of H2 are used?
elena-s [515]

Mass of PH3= 6.086 g

<h3>Further explanation</h3>

Given

6.0 L of H2

Required

mass of PH3

Solution

Reaction

P4 + 6H2 → 4PH3

Assumed at STP ( 1 mol gas=22.4 L)

Mol of H2 for 6 L :

= 6 : 22.4 L

= 0.268

From the equation, mol PH3 :

= 4/6 x moles H2

= 4/6 x 0.268

= 0.179

Mass PH3 :

= 0.179 x 33,99758 g/mol

= 6.086 g

5 0
2 years ago
calculate the (m/v) of nacl of a solution made by diluting 25.0 ml of a 7.50 (m/v)% NaCl solution to a total volume of 75.00 ml
postnew [5]

Answer:

c

Explanation:

8 0
3 years ago
Read 2 more answers
How many visible impact craters does the moon contain?
frez [133]
I believe the answer is B. a million or more.
5 0
3 years ago
I really need help pls, will pay anything
Triss [41]

Explanation:

For the first part,

 Reaction equation:

         N₂  +  3H₂   →   2NH₃

Given:

Number of moles of NH₃  = 6 moles

Unknown:

Number of moles of N₂  = ?

Solution:

   N₂  +  3H₂   →   2NH₃;

  From the reaction above, we solve from the known specie to the unknown. Ensure that the equation is balanced;

         2 moles of NH₃ is produced from 1 mole of N₂

        6 moles of NH₃ will be produced from \frac{6}{2}  mole of N₂

                                                                      = 3moles of N₂

The number of moles of N₂ is 3 moles

ii.

Given parameters:

Number of moles of sulfur = 2.4moles

Molar mass of sulfur  = 32.07g/mol

Unknown:

Mass of sulfur  = ?

Solution:

The number of moles of any substance can be found using the expression below;

 Number of moles  = \frac{mass}{molar mass}

  Mass of sulfur  = number of moles of sulfur x molar mass

Insert the parameters and solve;

    Mass of sulfur  = 2.4 x 32.07  = 76.97g

6 0
3 years ago
How much heat do you need to raise the temperature of 100g of aluminum from 30 C to 150 C
SVEN [57.7K]

Answer:

Q = 10.8 KJ

Explanation:

Given data:

Mass of Al= 100g

Initial temperature = 30°C

Final temperature = 150°C

Heat required = ?

Solution:

Specific heat of Al = 0.90 j/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 150°C - 30°C

ΔT = 120°C

Q = 100g×0.90 J/g.°C× 120°C

Q = 10800 J       (10800j×1KJ/1000 j)

Q = 10.8 KJ

4 0
3 years ago
Read 2 more answers
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